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Unformatted text preview: ) / ( n2) = p 21 , 026 . 1 / (72) = 64 . 85 . Then SE b 1 = s y  x / p ∑ ( x i¯ x ) 2 = 64 . 85 / √ 877 . 74 = 2 . 19 . From the back of the book, t . 975 = 2 . 571 on df = 72 = 5 . So a 95% conﬁdence interval is 25 . 01 ± 2 . 571(2 . 19) giving (19.4,30.6) (c) Test H : β 1 = 0 at the 5% signiﬁcance level. What does this test imply about the relationship between fatfree mass and energy expenditure? Answer: Since the 95% conﬁdence interval does not include zero, we reject H : β 1 = 0 at the 5% signiﬁcance level. There is a signiﬁcant (positive) linear relationship between energy expenditure and fatfree mass. (d) Answer: At X = 65 kg, we have ˆ Y = 607 . 3 + 25 . 01 × 65 ≈ 2233 kcal...
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This note was uploaded on 12/14/2011 for the course STAT 205 taught by Professor Hendrix during the Fall '09 term at South Carolina.
 Fall '09
 Hendrix

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