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Unformatted text preview: a . If b is a proper factor of a , then m.b/ < m.a/ , by Lemma 6.6.1 . Now if a 1 R a 2 R is a strictly increasing sequence of principal ideals, then for each i , a i C 1 is a proper factor of a i , and, therefore, m.a i C 1 / < m.a i / . If follows that the sequence is nite. n Lemma 6.6.14. If an integral domain R satises the ascending chain condition for principal ideals, then every nonzero, nonunit element of R has at least one factorization by irreducibles. Proof. This is exactly what is shown in the proof of Lemma 6.5.17 . n Lemma 6.6.15. If every irreducible element in an integral domain R is prime, then an element of R can have at most one factorization by irreducibles, up to permutation of the irreducible factors, and replacing irreducible factors by associates....
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This note was uploaded on 12/15/2011 for the course MAC 1105 taught by Professor Everage during the Fall '08 term at FSU.
 Fall '08
 EVERAGE
 Algebra

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