Unformatted text preview: r = 1 ± 2 i . Thus, y = t 1+2 i is a complex valued solution. Note that t 1+2 i = tt 2 i = t ( e ln t ) 2 i = te (2 ln t ) i = t (cos(2 ln t ) + i sin(2 ln t )) . The real and the imaginary parts are linearly independent and hence they give the fundamental solution set y 1 = t cos(2 ln t ) and y 2 = t sin(2 ln t ). The general solution (fot t > 0) is y = C 1 y 1 + C 2 y 2 = C 1 t cos(2 ln t ) + C 2 t sin(2 ln t ) . 1...
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 Spring '08
 TUNCER
 Complex number, general solution, c1 e−2t

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