This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Y will increase 15.8 units. 3) The test statistic is t = 15 . 8 4 . 499 = 3 . 512 > 1 . 746 = t . 05 , 16 Thus, we reject the null ( H : = 0) 1 4) Following the formula b t 2 se b , we obtain the 99% CI to be 15 . 8 2 . 921 * 4 . 499 = (2 . 658 , 28 . 942). We are 99% condent that the true value falls between 2.658 and 28.942. 5) The correlation r = R 2 where R 2 = SS Regr SS Total = 67525 87021 = 0 . 776. Thus, r = 0 . 88. See notes for the interpretation. 6) The test statistic is t = . 88 q 1. 776 16 = 7 . 43 > 1 . 746 = t . 05 , 16 Thus, we still reject H which is consistent with our part (3). This is a 1sided test where H a : < 0. 2...
View Full
Document
 Spring '08
 TA
 Statistics

Click to edit the document details