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Unformatted text preview: 2 ) = 7 . ( 2 1 + 0 . 50 1 . 3271 2 ) = 4 . 9 m . 2. A planet of radius 8 . 00 10 3 km spins with an angular velocity of 20 . 105 rad/s about an axis through the North Pole. What is the ratio of the normal force experienced by a person at the equator to that experienced by a person at the North Pole? Assume a constant gravitational acceleration of 1.60 m/s 2 and that both people are stationary relative to the planet and are at sea level. At the North Pole we have N NPmg = 0 = N NP = mg , while at the equator we have N eqmg =m 2 R = N eq = mgm 2 R . Thus the ratio N eq /N NP is given by: N eq N NP = 1 2 R g = 1(2 . 00 104 ) 2 8 . 00 10 6 1 . 60 = 1 . 000. 200 = 0 . 800 ....
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This note was uploaded on 12/15/2011 for the course PHY 2053 taught by Professor Buchler during the Fall '06 term at University of Florida.
 Fall '06
 Buchler
 Physics, Friction

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