Unformatted text preview: After time t , x A =6 . 00 + 4 . 00 × t , and x B = 5 . 003 . 00 × t . When they meet (at t meet ), x A = x B , i.e., x A =6 . 00 + 4 . 00 × t meet = 5 . 003 . 00 × t meet = x B . = ⇒ t meet = 11 . 00 / 7 . 00 hr = 1 . 57 hr . b) How far are they from the ±agpole when they meet? Consider the time it takes each to reach the position x . t A = x(6 . 00) 4 . 00 , t B = x5 . 00 (3 . 00) . When they meet (at x meet ), t A = t B . Thus: t A = x meet(6 . 00) 4 . 00 = x meet5 . 00 (3 . 00) = t B = ⇒ ( 1 3 . 00 + 1 4 . 00 ) × x meet = 5 . 00 3 . 006 . 00 4 . 00 , i . e ., x meet = 2 . 00 7 . 00 km = 0 . 286 km ....
View
Full Document
 Fall '06
 Buchler
 Physics, Scalar, Velocity, 1.57 hr

Click to edit the document details