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Unformatted text preview: After time t , x A =6 . 00 + 4 . 00 t , and x B = 5 . 003 . 00 t . When they meet (at t meet ), x A = x B , i.e., x A =6 . 00 + 4 . 00 t meet = 5 . 003 . 00 t meet = x B . = t meet = 11 . 00 / 7 . 00 hr = 1 . 57 hr . b) How far are they from the agpole when they meet? Consider the time it takes each to reach the position x . t A = x(6 . 00) 4 . 00 , t B = x5 . 00 (3 . 00) . When they meet (at x meet ), t A = t B . Thus: t A = x meet(6 . 00) 4 . 00 = x meet5 . 00 (3 . 00) = t B = ( 1 3 . 00 + 1 4 . 00 ) x meet = 5 . 00 3 . 006 . 00 4 . 00 , i . e ., x meet = 2 . 00 7 . 00 km = 0 . 286 km ....
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This note was uploaded on 12/15/2011 for the course PHY 2053 taught by Professor Buchler during the Fall '06 term at University of Florida.
 Fall '06
 Buchler
 Physics

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