Unformatted text preview: After the collision the two skaters move as a unit at 4.0 m/s. The impact time is 0.140 s. a) What is the magnitude of the average force experienced by each skater? Using ¯ F ∆ t = m ∆ v , we ﬁnd for the ﬁrst skater: ¯ F = m ∆ v ∆ t = 63 . × − 8 . . 140 = − 3600 N . The forces on the two skaters are equal and opposite. They are both of magnitude 3600 N. b) What is the mass of the second skater? Using ¯ F ∆ t = m ∆ v for the second skater, we ﬁnd: m = ¯ F ∆ t ∆ v = 3600 × . 14 4 . = 126 kg ....
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 Fall '06
 Buchler
 Physics, Force, Mass, Work, Average Force, Wnet, 0.450 kg

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