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Unformatted text preview: After the collision the two skaters move as a unit at 4.0 m/s. The impact time is 0.140 s. a) What is the magnitude of the average force experienced by each skater? Using F t = m v , we nd for the rst skater: F = m v t = 63 . 8 . . 140 = 3600 N . The forces on the two skaters are equal and opposite. They are both of magnitude 3600 N. b) What is the mass of the second skater? Using F t = m v for the second skater, we nd: m = F t v = 3600 . 14 4 . = 126 kg ....
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This note was uploaded on 12/15/2011 for the course PHY 2053 taught by Professor Buchler during the Fall '06 term at University of Florida.
 Fall '06
 Buchler
 Physics

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