MAT4375 HW-#2, 1999

MAT4375 HW-#2, 1999 - MAT4375 HW\#2, 1999

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MAT4375 HW\#2, 1999 http://aix1.uottawa.ca/~mat4375/Solutions/hw3.html 1 of 6 10/2/2007 8:26 PM 204.4 556.6 x 1 = 130.0 355.0 x 2 = 13825.3 23823.4 23823.4 73107.4 S 1 = 8632.0 19616.7 19616.7 55964.5 S 2 = T 2 : = [X 1 -X 2 -( μ 1 - μ 2 )] [(1/n 1 +1/n 2 )S pooled ] -1 [X 1 -X 2 -( μ 1 - μ 2 )] > ((n 1 +n 2 -2)/(n 1 +n 2 -p-1))F α (p, n 1 +n 2 -p-1) 10963.7 21505.5 21505.5 63661.3 S pooled = . MAT4375 HW#2, 1999 © A.R. Dabrowski, 1999 Problem 6.7 Problem 6.8 Problem 6.13 Problem 6.14 Problem 7.21 Due to html limitations, ``X- bar'' will be noted X . From the fourth edition of Johnson and Wichern Problem 6.7 Follow example 6.4. Here n 1 = 45, n 2 = 45, The test is Given by Result 6.2 page 305: Reject H 0 if Here the critical value is c 2 = 6.26 and Thus T 2 16.1 > 6.26 and we reject H 0 . The linear combination of components most responsible for rejection is proportional to
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MAT4375 HW-#2, 1999 - MAT4375 HW\#2, 1999

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