ME350 F11 HW3 SOLUTION Synthesis

ME350 F11 HW3 SOLUTION Synthesis - Revised 9/30/11 ME350...

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Revised 9/30/11 ME350 F11 HW3 Problem 1 Solution (Graphical Method) (25 points) Grading rubric: 25 points total 10 points for correct location of first ground pivot o 10 points if within 10mm o 5 points if within 20mm o 0 points if farther away 10 points for correct location of second ground pivot o 10 points if within 10mm o 5 points if within 20mm o 0 points if farther away 5 points for showing their work (perpendicular bisector lines constructed). The students do not need to show the compass arcs, since two methods were demonstrated in lecture. Problem 2 Solution (Analytical Method) (25 points)
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Revised 9/30/11 Looking at the first position of the part, and choosing a point in the top right corner to be our precision point, we have the following: The deltas are represented by the light blue arrows in the figure above. Since the distances in the problem are given in Cartesian coordinates, and MATLAB can handle this, we keep the Cartesian coordinates in this case instead of changing it to polar coordinates. (4 pts for deltas. Deltas can also be expressed in polar coordinates. Values of delta may be different if the students chose to use a different precision point. OK if the students measure the
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This note was uploaded on 12/16/2011 for the course ME 350 taught by Professor Kazusaitou during the Fall '11 term at University of Michigan.

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ME350 F11 HW3 SOLUTION Synthesis - Revised 9/30/11 ME350...

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