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# Sol4-32p3 - [1 d(Ca/d(t = ra Ca*voN 2 d(Cb/d(t = ra voN(Cb...

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Unformatted text preview: [1] d(Ca)/d(t) = ra - Ca*voN 2] d(Cb)/d(t) = ra - voN*(Cb- 10.93) 3] d(Cc)/d(t) = -ra - vo*CcN 4] d(Cd)/d(t) = -ra - vo*CdN Explicit equations as entered by the user _1] Kc = 1.08 2] k = 0.00009 . 3] ra = -k*(Ca*Cb - Cc*Cd/Kc) ' 4] v0 = 0.05 _ 5] V0 = 200 6] V = Vo + vo*t 7] X=1— Ca/7.72 i).(|e+i) -l.6e—3 . —3.2e-3 --l.8e-3 \ -6.-le—3 -8.0e—3 o 595..t 0 2 976 8928 1 l 904 l 4880 Polymath solution P4-32 (c) Change the value of v0 and CA0 in the Polymath program to see the changes. P4-32 ((1) As ethanol evaporates as fast as it forms: Now using part (b) remaining equations, Polymath code: CD=0 See Polymath program P4—32—d.pol. POLYMATH Results Calculated values of the DES! variables Variable initial value minimal value maximal value final value t 0 Ca 7.72 Cb 10.93 k 9.0E—05 ra 70.0075942 — vo 0.05 V0 200 . 0519348 .9932872 . OE-OS . 0075942 .05 20 OOKDONOO 2.0e+1 1.6i:+l l.2e+l 8. 0 e-H] 4.0e+0 0.0e+l)_ " “ " , 0 2976 S952t 8928 11904 14880 1.0 0.8 0.6 0.4 0.2 01'. 0 1189 2378 t 3567 4756 5945 6000 6000 7.72 0.0519348 10.93 7.8939348 9.0E—05 9.0E—05 —3.69E—05 —3.69E—05 0.05 ' 0.05 200 200 4-62 ...
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