final-exam1-solution

# final-exam1-solution - CSE 143 SUMMER 2010 FINAL EXAM...

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1 CSE 143 SUMMER 2010 FINAL EXAM SOLUTION (PART 1) 1. (12 points) Using recursion , write a method mod that takes two integers a and b as parameters and returns the remainder of a divided by b , i.e. , a % b . You may use + , - , comparison operators ( > , >= , < , <= , == , != ), and Boolean operators ( , || ). You may NOT use * , / , % , any loops ( i.e. , for or while ) or any method from the Java library. You may assume that a is greater than or equal to zero and b is greater than zero. You may find the following equality useful: a % b = (a – b) % b public static int mod( int a, int b) { if (a < b) { return a; } else { return mod(a - b, b); } } A bunch of people did everything properly except to say “return” in the recursive call. That was worth 3 points. 2. (12 points) Using recursion , write a method parity that takes a string as a parameter and returns the string "odd" if the string has an odd number of characters and "even" if the string has an even number of characters. For example, the call parity("abcdef") will return "even" , while will return "odd" . You may NOT use any loops (

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## This document was uploaded on 12/17/2011.

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final-exam1-solution - CSE 143 SUMMER 2010 FINAL EXAM...

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