Unformatted text preview: cen54261_ch10.qxd 12/2/03 10:55 AM Page 461 PART FLUID MECHANICS 2 461 cen54261_ch10.qxd 12/2/03 10:55 AM Page 462 cen54261_ch10.qxd 1/8/04 8:12 AM Page 463 CHAPTER INTRODUCTION TO FLUID
n the second part of the text we present the fundamentals of fluid mechanics. In this introductory chapter, we introduce the basic concepts commonly used in the analysis of fluid flow to avoid any misunderstandings.
We start with a discussion of the numerous ways of classification of fluid
flow, such as viscous versus inviscid regions of flow, internal versus external
flow, compressible versus incompressible flow, laminar versus turbulent flow,
natural versus forced flow, and steady versus unsteady flow. We also discuss
the no-slip condition, which is responsible for the development of boundary
layers adjacent to the solid surfaces, and the no-temperature-jump condition.
We continue with a brief history of the development of fluid mechanics. Then
we discuss the property viscosity, which plays a dominant role in most aspects
of fluid flow. Finally, we present the property surface tension, and determine
the capillary rise from static equilibrium conditions. I 10
10–1 Classification of Fluid
10–2 The No-Slip Condition 467
10–3 History of Fluid Mechanics 468
10–4 Vapor Pressure and
10–5 Viscosity 470
10–6 Surface Tension and Capillary
References and Suggested
Problems 481 463 cen54261_ch10.qxd 12/2/03 10:55 AM Page 464 464
FUNDAMENTALS OF THERMAL-FLUID SCIENCES 10–1 I CLASSIFICATION OF FLUID FLOWS In Chap. 1 we defined fluid mechanics as the science that deals with the behavior of fluids at rest or in motion, and the interaction of fluids with solids or
other fluids at the boundaries. There is a wide variety of fluid flow problems
encountered in practice, and it is usually convenient to classify them on the
basis of some common characteristics to make it feasible to study them in
groups. There are many ways to classify the fluid flow problems, and here we
present some general categories. Viscous versus Inviscid Regions of Flow
When two fluid layers move relative to each other, a friction force develops
between them and the slower layer tries to slow down the faster layer. This internal resistance to flow is called the viscosity, which is a measure of internal
stickiness of the fluid. Viscosity is caused by cohesive forces between the
molecules in liquids, and by molecular collisions in gases. There is no fluid
with zero viscosity, and thus all fluid flows involve viscous effects to some
degree. Flows in which the effects of viscosity are significant are called
viscous flows. However, in many flows of practical interest, there are regions
(typically regions not close to solid surfaces) where viscous forces are negligibly small compared to inertial or pressure forces. Neglecting the viscous
terms in such inviscid flow regions greatly simplifies the analysis without
much loss in accuracy. Internal versus External Flow External
flow Water Air Internal
flow FIGURE 10–1
Internal flow of water in a pipe and
the external flow of air over the same
pipe. A fluid flow is classified as being internal or external, depending on
whether the fluid is forced to flow in a confined channel or over a surface.
The flow of an unbounded fluid over a surface such as a plate, a wire, or a
pipe is external flow. The flow in a pipe or duct is internal flow if the fluid
is completely bounded by solid surfaces. Water flow in a pipe, for example,
is internal flow, and airflow over an exposed pipe during a windy day is external flow (Fig. 10–1). The flow of liquids in a duct is called open-channel
flow if the duct is only partially filled with the liquid and there is a free surface. The flow of water in rivers and irrigation ditches are examples of such
flows. Compressible versus Incompressible Flow
A fluid flow is classified as being compressible or incompressible, depending
on the density variation of the fluid during flow. The densities of liquids are
essentially constant, and thus the flow of liquids is typically incompressible.
Therefore, liquids are usually classified as incompressible substances. A pressure of 210 atm, for example, causes the density of liquid water at 1 atm to
change by just 1 percent. Gases, on the other hand, are highly compressible. A
pressure change of just 0.01 atm, for example, causes a change of 1 percent in
the density of atmospheric air. However, gas flows can be treated as incompressible if the density changes are under about 5 percent, which is usually the
case when the flow velocity is less than 30 percent of the speed of sound in cen54261_ch10.qxd 12/2/03 10:55 AM Page 465 465
CHAPTER 10 that gas (i.e., the Mach number of flow is less than 0.3). The speed of sound
in air at room temperature is 346 m/s. Therefore, the compressibility effects of
air can be neglected at speeds under about 100 m/s. Note that the flow of a gas
is not necessarily a compressible flow.
Small density changes of liquids corresponding to large pressure changes
can still have important consequences. The irritating “water hammer” in water pipes, for example, is caused by the vibrations of the pipe generated by the
reflection of pressure waves following the sudden closing of the valves. Laminar versus Turbulent Flow
Some flows are smooth and orderly while others are rather chaotic. The
highly ordered fluid motion characterized by smooth streamlines is called
laminar. The flow of high-viscosity fluids such as oils at low velocities is
typically laminar. The highly disordered fluid motion that typically occurs at
high velocities and is characterized by velocity fluctuations is called turbulent. The flow of low-viscosity fluids such as air at high velocities is typically turbulent. The flow regime greatly influences the required power for
pumping. Natural (or Unforced) versus Forced Flow
A fluid flow is said to be natural or forced, depending on how the fluid motion
is initiated. In forced flow, a fluid is forced to flow over a surface or in a pipe
by external means such as a pump or a fan. In natural flows, any fluid motion
is due to natural means such as the buoyancy effect, which manifests itself as
the rise of the warmer (and thus lighter) fluid and the fall of cooler (and thus
denser) fluid. This thermosiphoning effect is commonly used to replace
pumps in solar water heating systems by placing the water tank sufficiently
above the solar collectors (Fig. 10–2). Cold
water Steady versus Unsteady Flow
water rising Hot
water cto lar rs rad iat ion Cold
(above the top
of collectors) So lar co lle So The terms steady and uniform are used frequently in engineering, and thus it
is important to have a clear understanding of their meanings. The term steady
implies no change at a point with time. The opposite of steady is unsteady.
The term uniform implies no change with location over a specified region.
These meanings are consistent with their everyday use (steady girlfriend, uniform distribution, etc.).
The terms unsteady and transient are often used interchangeably, but these
terms are not synonyms. In fluid mechanics, unsteady is the most general term
that applies to any flow that is not steady, but transient is typically used for
developing flows. When a rocket engine is fired up, for example, there are
transient effects as the pressure builds up inside the rocket engine, the flow accelerates, etc., until the engine settles down and operates steadily. The term
periodic refers to the kind of unsteady flow in which the flow oscillates about
a steady mean.
Many devices such as turbines, compressors, boilers, condensers, and heat
exchangers operate for long periods of time under the same conditions, and
they are classified as steady-flow devices. (Note that the flow field near the Dense cold
water sinking FIGURE 10–2
Natural circulation of water in a solar
water heater by thermosiphoning. cen54261_ch10.qxd 2/26/04 12:04 PM Page 466 466
FUNDAMENTALS OF THERMAL-FLUID SCIENCES (a) (b) FIGURE 10–3
Oscillating wake of a blunt-based
airfoil at Mach number 0.6. Photo
(a) is an instantaneous image while
photo (b) is a long-exposure (timeaveraged) image. Photos by A.
Dyment, J.P. Flodrops, and P. Gryson.
Used by permission of Arthur
Dyment. rotating blades of a turbomachine is of course unsteady, but we consider the
overall flow field rather than the details at some localities when we classify
devices.) During steady flow, the fluid properties can change from point to
point within a device, but at any fixed point they remain constant. Therefore,
the volume, the mass, and the total energy content of a steady-flow device or
flow section remain constant in steady operation.
Steady-flow conditions can be closely approximated by devices that are intended for continuous operation such as turbines, pumps, boilers, condensers,
and heat exchangers of power plants or refrigeration systems. Some cyclic devices, such as reciprocating engines or compressors, do not satisfy the steadyflow conditions since the flow at the inlets and the exits is pulsating and not
steady. However, the fluid properties vary with time in a periodic manner, and
the flow through these devices can still be analyzed as a steady-flow process
by using time-averaged values for the properties.
Some fascinating visualizations of fluid flow are provided in the book An
Album of Fluid Motion by Milton Van Dyke (1982). A nice illustration of an
unsteady-flow field is shown in Fig. 10–3, taken from Van Dyke’s book. Figure 10–3a is an instantaneous snapshot from a high-speed motion picture; it
reveals large, alternating, swirling, turbulent eddies that are shed into the periodically oscillating wake from the blunt base of the object. The eddies produce shock waves that move upstream alternately over the top and bottom
surfaces of the airfoil in an unsteady fashion. Figure 10–3b shows the same
flow field, but the film is exposed for a longer time so that the image is time
averaged over 12 cycles. The resulting time-averaged flow field appears
“steady” since the details of the unsteady oscillations have been lost in the
One of the most important jobs of an engineer is to determine whether it is
sufficient to study only the time-averaged “steady” flow features of a problem, or whether a more detailed study of the unsteady features is required. If
he or she were interested only in the overall properties of the flow field, such
as the time-averaged drag coefficient, the mean velocity and pressure fields,
etc., a time-averaged description like that of Fig. 10–3b, time-averaged experimental measurements, or an analytical or numerical calculation of the
time-averaged flow field would be sufficient. However, if he or she were interested in details about the unsteady-flow field, such as flow induced vibrations, unsteady pressure fluctuations, or the sound waves emitted from the
turbulent eddies or the shock waves, a time-averaged description of the flow
field would be insufficient.
Most of the analytical and computational examples provided in this textbook deal with steady or time-averaged flows, although we occasionally point
out some relevant unsteady-flow features as well when appropriate. One-, Two-, and Three-Dimensional Flows
A flow field is best characterized by the velocity distribution, and thus a flow
is said to be one-, two-, or three-dimensional if the flow velocity varies in one,
two, or three primary dimensions, respectively. A typical fluid flow involves a
three-dimensional geometry and the velocity may vary in all three dimensions
rendering the flow three-dimensional [ (x, y, z) in rectangular or (r, u, z)
in cylindrical coordinates]. However, the variation of velocity in certain
directions can be small relative to the variation in other directions, and can be cen54261_ch10.qxd 12/2/03 10:55 AM Page 467 467
CHAPTER 10 ignored with negligible error. In such cases, the flow can be modeled conveniently as being one- or two-dimensional, which is easier to analyze.
When the entrance effects are far upstream of the region of interest, fully
developed fluid flow in a circular pipe is one-dimensional since the velocity
varies in the radial r-direction but not in the angular u- or axial z-directions
(Fig. 10–4). That is, the velocity profile is the same at any axial z-location,
and it is symmetric about the axis of the pipe. Note that even in this simple
flow, the velocity cannot be uniform across the cross section of the pipe because of the no-slip condition. However, at a well-rounded entrance to the
pipe, the velocity profile may be approximated as nearly uniform across the
pipe, since the velocity is constant at all radii except very close to the pipe
wall (Fig. 10–5)
A flow may be approximated as two-dimensional when the aspect ratio
is large and the flow does not change appreciably along the longer dimension. For example, the flow of air over a car antenna can be considered twodimensional except near its ends since the antenna’s length is much greater than
its diameter, and the airflow hitting the antenna is fairly uniform (Fig. 10–6). EXAMPLE 10–1 Velocity profile
(remains unchanged) Axisymmetric Flow over a Bullet
The velocity profile at the wellrounded entrance to a pipe is nearly
uniform (one-dimensional). SOLUTION It is to be determined whether airflow over a bullet is one-, two-, or
Assumptions There are no significant winds and the bullet is not spinning.
Analysis The bullet possesses an axis of symmetry, and airflow is parallel to
this axis. Therefore, airflow is symmetric about the axis, and such flows are
said to be axisymmetric. A bullet piercing through air is an example of axisymmetric flow. The velocity in this case varies with the axial distance x and the radial distance r, but not with the angle u. Therefore, airflow over the bullet is
two-dimensional. I z FIGURE 10–4
One-dimensional flow in a
circular pipe. Consider a bullet piercing through calm air. Determine if airflow over the bullet
during its flight is one-, two-, or three-dimensional (Fig. 10–7). 10–2 (r) r THE NO-SLIP CONDITION Consider the flow of a fluid in a stationary pipe or over a solid surface that is
nonporous (i.e., impermeable to the fluid). All experimental observations indicate that a fluid in motion comes to a complete stop at the surface and assumes a zero velocity relative to the surface. That is, a fluid in direct contact
with a solid sticks to the surface and there is no slip. This is known as the noslip condition, and it is due to the fluid viscosity.
The no-slip condition is responsible for the development of the velocity profile. Because of friction between the fluid layers, the layer that sticks to the
wall slows the adjacent fluid layer, which slows the next layer, and so on. A
fluid layer adjacent to a moving surface has the same velocity as the surface.
A consequence of the no-slip condition is that all velocity profiles must have
zero values with respect to the surface at the points of contact between a fluid
and a solid surface (Fig. 10–8). The only exception to the no-slip condition occurs in extremely rarefied gases. FIGURE 10–6
Flow over a car antenna is
except near the top and bottom of the
x FIGURE 10–7
Axisymmetric flow over a bullet. cen54261_ch10.qxd 12/2/03 10:55 AM Page 468 468
FUNDAMENTALS OF THERMAL-FLUID SCIENCES
of fluid layers
surface Solid block FIGURE 10–8
A fluid flowing over a stationary
surface comes to a complete stop at
the surface because of the no-slip
condition. FIGURE 10–9
A lot can be learned about fluid
mechanics by observing nature. A similar phenomenon occurs for the temperature. When two bodies at different temperatures are brought into contact, heat transfer occurs until both
bodies assume the same temperature at the points of contact. Therefore, a fluid
and a solid surface have the same temperature at the points of contact. This is
known as no-temperature-jump condition. 10–3 I HISTORY OF FLUID MECHANICS Nature is like an exhibit hall for the applications of fluid mechanics, and we
can learn a lot about the fundamentals of fluid mechanics and be inspired by
carefully observing nature (Fig. 10–9). The development of fluid mechanics
started in ancient times with the need to build irrigation systems and to design
better ships with oars. The earliest contribution to the field was made by
Archimedes (285–212 B.C.) who formulated the principles of buoyancy of
submerged bodies and flotation, and applied those principles to determine the
gold content of the crown of King Hiero I. At about the same time, the Roman
engineers built an extensive network of fresh-water supply. There was no significant development in fluid mechanics through the Middle Ages until
Leonardo da Vinci (1459–1519) conducted several experiments and derived
the conservation of mass equation for one-dimensional steady flow.
The development of fluid mechanics continued along two different paths:
on one, the mathematicians and physicists developed the theory and applied
it to “idealized” problems that did not have much practical value. On the
other path, engineers developed empirical equations that could be used in the
design of fluid systems in a limited range. The lack of communication between these two groups hindered the development of fluid mechanics for a
long time. The development of the laws of motion by Isaac Newton
(1649–1727) and the linear law of viscosity for the so-called Newtonian fluids set the stage for advances in fluid mechanics. Applying these laws to a
fluid element, Leonhard Euler (1707–1783) obtained the differential equations for fluid motion in 1755. Daniel Bernoulli (1700–1782) developed the
energy equation for incompressible flow in 1738. Lord Rayleigh (1849–1919)
developed the powerful dimensional analysis technique. Osborn Reynolds
(1849–1912) conducted extensive experiments with pipe flow and in 1883
came up with the dimensionless number that bears his name.
The general equations of fluid motion that include the effects of fluid friction, known as the Navier–Stokes equations, were developed by Claude
Louis Marie Navier (1785–1836) in 1827 and independently by George
Gabriel Stokes (1819–1903) in 1845. These equations were of little use at the
time because they were too difficult to solve. Then in a pioneering paper in
1904, Ludwig Prandtl (1875–1953) showed that fluid flows can be divided
into a layer near the walls, called the boundary layer, where the friction effects are significant and an outer layer where such effects are negligible, thus
the Euler and Bernoulli equations are applicable. Theodore von Karman
(1889–1963) and Sir Geoffrey I. Taylor (1886–1975) also contributed greatly
to the development of fluid mechanics in the twentieth century. The availability of high-speed computers in the last decades and the development of
numerical methods have made it possible to solve a variety of real-world
fluids problems and to conduct design and optimization studies through numerical simulation. cen54261_ch10.qxd 12/4/03 8:37 AM Page 469 469
CHAPTER 10 10–4 I VAPOR PRESSURE AND CAVITATION Recall that temperature and pressure are dependent properties for pure substances during phase-change processes, and there is one-to-one correspondence between temperatures and pressures. At a given pressure, the
temperature at which a pure substance changes phase is called the saturation
temperature, Tsat. Likewise, at a given temperature, the pressure at which a
pure substance changes phase is called the saturation pressure, Psat. At an absolute pressure of 1 standard atmosphere (1 atm or 101.325 kPa), for example,
the saturation temperature of water is 100°C. Conversely, at a temperature of
100°C, the saturation pressure of water is 1 atm.
Atmospheric air can be viewed as a mixture of dry air and water vapor, and
the atmospheric pressure is the sum of the pressure of dry air and the pressure
of water vapor. The pressure of a vapor, whether it exists alone or in a mixture
with other gases, is called the vapor pressure P . The vapor pressure constiυ
tutes a small fraction (usually under 3 percent) of the atmospheric pressure
since air is mostly nitrogen and oxygen, but the rate of evaporation from open
water bodies such as lakes is controlled by the vapor pressure. For example,
the saturation pressure of water at 20 C is 2.34 kPa. Therefore, a glass of water at 20 C left in a room at 1 atm will continue evaporating until the pressure
of the water vapor in the room rises to 2.34 kPa at which point phase equilibrium is established. This explains why water at 1 atm “evaporates” at temperatures below 100 C.
For phase-change processes between the liquid and vapor phases of a pure
substance, the saturation pressure and the vapor pressure are equivalent since
the vapor is pure. Note that the pressure value would be the same whether it is
measured in the vapor or liquid phase (provided that it is measured at a location close to the liquid–vapor interface to avoid the hydrostatic effects). Vapor
pressure increases with temperature. Thus, a substance at higher temperatures
boils at higher pressures. For example, water boils at 134 C in a pressure
cooker operating at 3 atm absolute pressure, but it boils at 93 C in an ordinary
pan at a 2000-m elevation, where the atmospheric pressure is 0.8 atm. The
saturation (or vapor) pressures are given in Appendices 1 and 2 for various
substances. A mini table for water is given in Table 10–1 for easy reference.
The reason for our interest in vapor pressure is the possibility of the liquid
pressure in liquid-flow systems dropping below the vapor pressure at some locations, and the resulting unplanned vaporization. For example, water at 10 C
will flash into vapor and form bubbles at locations (such as the tip regions of
impellers or suction sides of pumps) where the pressure drops below 1.23 kPa.
The vapor bubbles (called cavitation bubbles since they form “cavities” in
the liquid) collapse as they are swept away from the low-pressure regions,
generating highly destructive, extremely high-pressure waves. This phenomenon, which is a common cause for drop in performance and even the erosion
of impeller blades, is called cavitation, and it is an important consideration in
the design of hydraulic turbines and pumps (Fig. 10–10).
Cavitation must be avoided (or at least minimized) in flow systems since it
reduces performance, generates annoying vibrations and noise, and causes
damage to equipment. The pressure spikes resulting from the large number of
bubbles collapsing near a solid surface over a long period of time may cause
erosion, surface pitting, fatigue failure, and the eventual destruction of the TABLE 10–1
Saturation (boiling) pressure of
water at various temperatures
101.3 (1 atm)
8581 FIGURE 10–10
Cavitation damage on a 16-mm by
23-mm aluminum sample tested at
60 m/s for 2.5 h. The sample was
located at the cavity collapse region
downstream of a cavity generator
specifically designed to produce high
damage potential (Photo by David
Stinebring, Pennsylvania State
University). cen54261_ch10.qxd 12/2/03 10:55 AM Page 470 470
FUNDAMENTALS OF THERMAL-FLUID SCIENCES components or machinery. The presence of cavitation in a flow system can be
sensed by its characteristic tumbling sound. EXAMPLE 10–2 Minimum Pressure to Avoid Cavitation In a water distribution system, the temperature of water is observed to be as
high as 30 C. Determine the minimum pressure allowed in the system to avoid
cavitation. SOLUTION The minimum pressure in a water distribution system to avoid cavitation is to be determined.
Properties The vapor pressure of water at 30 C is 4.25 kPa (Table 10–1).
Analysis To avoid cavitation, the pressure anywhere in flow should not be allowed to drop below the vapor (or saturation ) pressure at the given temperature.
force Water Drag
force FIGURE 10–11
A moving fluid exerts a drag force on
a body, partly because of friction
caused by viscosity.
N′ u = Force F
Velocity dβ y
x M 4.25 kPa Therefore, the pressure should be maintained above 4.25 kPa everywhere in
Discussion Note that the vapor pressure increases with increasing temperature, and thus the risk of cavitation is greater at higher fluid temperatures. Air N [email protected] C u= 0
u(y) = FIGURE 10–12
The behavior of a fluid between two
parallel plates when the upper plate
moves with a constant velocity. 10–5 I VISCOSITY When two solid bodies in contact move relative to each other, a friction force
develops at the contact surface in the direction opposite to motion. To move a
table on the floor, for example, we have to apply a force to the table in the
horizontal direction large enough to overcome the friction force. The magnitude of the force needed to move the table depends on the friction coefficient
between the table and the floor.
The situation is similar when a fluid moves relative to a solid, or when two
fluids move relative to each other. We move with relative ease in air, but not
so in water. Moving in oil would be even more difficult, as can be observed by
the slower downward motion of a glass ball dropped in a tube filled with oil.
It appears that there is a property that represents the internal resistance of a
fluid to motion or the “fluidity,” and that property is the viscosity. The force a
flowing fluid exerts on a body in the flow direction is called the drag force,
and the magnitude of this force depends, in part, on viscosity (Fig. 10–11).
To obtain a relation for viscosity, consider a fluid layer between two very
large parallel plates (or equivalently, two parallel plates immersed in a large
body of a fluid) separated by a distance (Fig. 10–12). Now a constant parallel force F is applied to the upper plate while the lower plate is held fixed.
After the initial transients, it is observed that the upper plate moves continuously under the influence of this force at a constant velocity . The fluid in
contact with the upper plate sticks to the plate surface and moves with it at the
same velocity, and the shear stress t acting on this fluid layer is
A (10–1) cen54261_ch10.qxd 12/2/03 10:55 AM Page 471 471
CHAPTER 10 where A is the contact area between the plate and the fluid. Note that the fluid
layer deforms continuously under the influence of shear stress, as expected.
The fluid in contact with the lower plate assumes the velocity of that plate,
which is zero (again because of the no-slip condition). In steady operation, the
fluid velocity between the plates in most cases varies linearly between 0 and
, and thus the velocity profile and the velocity gradient are
y u(y) du
dy and (10–2) where y is the vertical distance from the lower plate.
During a differential time interval dt, the fluid particles along a vertical line
MN rotate through a differential angle db while the upper plate moves a
differential distance da
dt. The angular displacement or deformation (or
shear strain) can be expressed as
db tan b dt da du
dy (10–3) Rearranging, the rate of deformation under the influence of shear stress t
dy (10–4) Thus we conclude that the rate of deformation of a fluid element is equivalent
to the velocity gradient du/dy. Further, it can be verified experimentally that
for most fluids the rate of deformation (and thus the velocity gradient) is directly proportional to the shear stress t,
dt t or du
dy t (10–5) Fluids for which the rate of deformation is proportional to the shear stress are
called Newtonian fluids after Sir Isaac Newton, who expressed it first in
1687. Most common fluids such as water, air, gasoline, and oils are Newtonian fluids. Blood and liquid plastics are examples of non-Newtonian fluids.
In one-dimensional flow of Newtonian fluids, shear stress can be expressed
by the linear relationship,
t Shear stress: du
dy 2 (N/m ) F tA mA du
dy (N) Oil Viscosity = Slope µ= (10–6) where the constant of proportionality m is called the dynamic (or absolute)
viscosity of the fluid, whose unit is kg/m s, or equivalently, N s/m2 (or Pa s
where Pa is the pressure unit pascal). A common viscosity unit is poise, which is
equivalent to 0.1 Pa s (or centipoise, which is one-hundredth of a poise). A plot
of shear stress versus the rate of deformation (velocity gradient) for a Newtonian fluid is a straight line whose slope is the viscosity of the fluid, as shown in
Fig. 10–13. Note that viscosity is independent of the rate of deformation.
The shear force acting on a Newtonian fluid layer (or, by Newton’s third
law, the force acting on the plate) is
Shear force: Shear stress, τ (10–7) a τ
du / dy = a
b Water b Air
Rate of deformation, du/dy FIGURE 10–13
The rate of deformation (velocity
gradient) of a Newtonian fluid is
proportional to shear stress, and the
constant of proportionality is the
viscosity. cen54261_ch10.qxd 12/4/03 8:39 AM Page 472 472
FUNDAMENTALS OF THERMAL-FLUID SCIENCES where again A is the contact area between the plate and the fluid. Then the
force F required to move the upper plate in Fig. 10–12 at a constant velocity
of while the lower plate remains stationary is
F Shear stress, τ
Newtonian Dilatant Rate of deformation, du/dy FIGURE 10–14
Variation of shear stress with the rate
of deformation for Newtonian and
non-Newtonian fluids (the slope of a
curve at a point is the apparent
viscosity of the fluid at that point).
Air at 20°C and 1 atm:
µ = 1.83 × 10–5 kg/m ⋅ s
υ = 1.52 × 10–5 m2/s
Air at 20°C and 4 atm:
µ = 1.83 × 10–5 kg/m ⋅ s
υ = 0.380 × 10–5 m2/s FIGURE 10–15
Dynamic viscosity, in general, does
not depend on pressure, but kinematic
viscosity does. mA (N) (10–8) This relation can alternately be used to calculate m when the force F is measured. Therefore, the experimental setup just described can be used to measure
the viscosity of fluids. Note that under identical conditions, the force F will
be very different for different fluids.
For non-Newtonian fluids, the relationship between shear stress and rate of
deformation is not linear, as shown in Fig. 10–14. The slope of the curve on
the t versus. du/dy chart is referred to as the apparent viscosity of the fluid.
Fluids for which the apparent viscosity increases with the rate of deformation
(such as solutions with suspended starch or sand) are referred to as dilatant or
shear thickening fluids, and those that exhibit the opposite behavior (the fluid
becoming less viscous as it is sheared harder, such as some paints, polymer
solutions, and fluids with suspended particles) are referred to as pseudoplastic or shear thinning fluids. Some materials such as toothpaste can resist a
finite shear stress and thus behave as a solid, but deform continuously when
the shear stress exceeds the yield stress and thus behave as a fluid. Such
materials are referred to as bingham plastic.
In fluid mechanics and heat transfer, the ratio of dynamic viscosity to density appears frequently. For convenience, this ratio is given the name kinem/r. Two common units of
matic viscosity υ and is expressed as υ
kinematic viscosity are m2/s and stoke (1 stoke 1 cm2/s 0.0001 m2/s).
In general, the viscosity of a fluid depends on both temperature and pressure, although the dependence on pressure is rather weak. For liquids, both the
dynamic and kinematic viscosities are practically independent of pressure,
and any small variation with pressure is usually disregarded, except at extremely high pressures. For gases, this is also the case for dynamic viscosity
(at low to moderate pressures), but not for kinematic viscosity since the density of a gas is proportional to its pressure (Fig. 10–15).
The viscosity of a fluid is a measure of its “stickiness” or “resistance to
shear.” It is due to the internal frictional force that develops between different
layers of fluids as they are forced to move relative to each other. Viscosity is
caused by the cohesive forces between the molecules in liquids, and by the
molecular collisions in gases, and it varies greatly with temperature. The viscosity of liquids decreases with temperature, whereas the viscosity of gases
increases with temperature (Fig. 10–16). This is because in a liquid the molecules possess more energy at higher temperatures, and they can oppose the
large cohesive intermolecular forces more strongly. As a result, the energized
liquid molecules can move more freely.
In a gas, on the other hand, the intermolecular forces are negligible, and the
gas molecules at high temperatures move randomly at higher velocities. This
results in more molecular collisions per unit volume per unit time, and therefore in greater resistance to flow. The viscosity of a fluid is directly related to
power needed to transport a fluid in a pipe or to move a body (such as a car in
air or a submarine in the sea) through a fluid. cen54261_ch10.qxd 12/2/03 10:55 AM Page 473 The kinetic theory of gases predicts the viscosity of gases to be proportional
to the square root of temperature. That is, mgas 2T . This prediction is confirmed by practical observations, but deviations for different gases need to be
accounted for by incorporating some correction factors. The viscosity of gases
is given as a function of temperature by the Sutherland correlation (from The
U.S. Standard Atmosphere) as
m Gases: aT1/2
1 b /T 473
Viscosity Liquids (10–9) where T is absolute temperature, and a and b are experimentally determined
constants. Note that measuring viscosities at two different temperatures is sufficient to determine these constants. For air, the values of these constants are
a 1.458 10 6 kg/(m s K1/2) and b 110.4 K at atmospheric conditions. The viscosity of gases is independent of pressure at low to moderate
pressures (from a few percent of 1 atm to several atm). But viscosity increases
at high pressures due to the increase in density.
For liquids, the viscosity is given as
m Liquids: a10 b/(T c) (10–10) where again T is absolute temperature, and a, b, and c are experimentally determined constants. For water, using the values a 2.414 10 5 N s/m2,
b 247.8 K, and c 140 K results in less than 2.5 percent error in viscosity
in the temperature range of 0 C to 370 C (Touloukian et al., 1975).
Consider a fluid layer of thickness within a small gap between two concentric cylinders, such as the thin layer of oil in a journal bearing. The gap between the cylinders can be modeled as two parallel flat plates separated by a
fluid. Noting that torque is T FR (force times the moment arm, which is the
radius R of the inner cylinder in this case), the tangential velocity is
(angular velocity times the radius), and taking the wetted surface area of the
inner cylinder to be A 2pRL by disregarding the shear stress acting on the
two ends of the inner cylinder, torque can be expressed as
T FR m 2pR3vL m 4p2R3 n L (10–11) where L is the length of the cylinder and n is the number of revolutions per
unit time, which is usually expressed in rpm (revolutions per minute). Note
that the angular distance traveled during one rotation is 2p radians, and thus
the relation between the angular velocity in rad/min and the rpm is v 2pn.
Equation 10–11 can be used to calculate the viscosity of a fluid by measuring
torque at a specified angular velocity. Therefore, two concentric cylinders can
be used as a viscometer, a device that measures viscosity.
The viscosities of some fluids at room temperature are listed in Table 10–2.
They are plotted against the temperature in Fig. 10–17. Note that the viscosities of different fluids differ by several orders of magnitude. Also note that it
is more difficult to move an object in a higher-viscosity fluid such as engine
oil than it is in a lower-viscosity fluid such as water. Liquids, in general, are
much more viscous than gases. Gases Temperature FIGURE 10–16
The viscosity of liquids decreases and
the viscosity of gases increases with
Dynamic viscosities of some fluids
at 1 atm and 20˚C (unless otherwise
100 C (liquid)
100 C (vapor)
Blood, 37 C
Hydrogen, 0 C Dynamic viscosity
, kg/m s
0.0000088 cen54261_ch10.qxd 12/4/03 8:40 AM Page 474 474
FUNDAMENTALS OF THERMAL-FLUID SCIENCES
0.1 Castor oil
SAE 10 oil
Glycerin Absolute viscosity µ , N ⋅ s/m2 0.06
0.02 SAE 30 oil
Crude oil (SG 0.86) 0.01
Mercury 1 × 10 –3 Carbon tetrachloride 6
2 Benzene Ethyl alcohol
Gasoline (SG 0.68) 1 × 10 –4 FIGURE 10–17
The variation of dynamic (absolute)
viscosities of common fluids
with temperature at 1 atm
(1 N · s/m2 1 kg/m · s
0.020886 lbf · s/ft2)
(from White). 6
Air 1 × 10 –5 Hydrogen 5
–20 0 EXAMPLE 10–3
cylinder Carbon Dioxide 20 40
Temperature, °C 100 120 Determining the Viscosity of a Fluid The viscosity of a fluid is to be measured by a viscometer constructed of two
40-cm-long concentric cylinders (Fig. 10–18). The outer diameter of the inner
cylinder is 12 cm, and the gap between the two cylinders is 0.15 cm. The inner cylinder is rotated at 300 rpm, and the torque is measured to be 1.8 N m.
Determine the viscosity of the fluid. SOLUTION The torque and the rpm of a double cylinder viscometer are
given. The viscosity of the fluid is to be determined.
Assumptions 1 The inner cylinder is completely submerged in oil. 2 The viscous effects on the two ends of the inner cylinder are negligible.
Analysis Solving Eq. 10–11 for viscosity and substituting the given values, the
viscosity of the fluid is determined to be R
n = 300 rpm
Shaft Fluid FIGURE 10–18
Schematic for Example 10–3. m T
4p2R3nL (1.8 N m)(0.0015 m)
4p2(0.06 m)3(300/60 1/s)(0.4 m) 0.158 N/m2 s cen54261_ch10.qxd 1/8/04 8:12 AM Page 475 475
CHAPTER 10 Courtesy Visuals
by Pegasus Courtesy Visuals
by Dennis Drenner FIGURE 10–19
Some consequences of
surface tension. Discussion Viscosity is a strong function of temperature, and a viscosity value
without a temperature is of little value. Therefore, the temperature of the fluid
should have also been measured during this experiment, and reported with this
calculation. 10–6 I SURFACE TENSION AND CAPILLARY EFFECT It is often observed that a drop of blood forms a hump on a horizontal glass,
a drop of mercury forms a near-perfect sphere and can be rolled just like a
steel ball over a smooth surface; water droplets from rain or dew hang from
branches or leaves of trees; a liquid fuel injected into an engine forms a mist
of spherical droplets; water dripping from a leaky faucet falls as spherical
droplets; and a soap bubble released into the air forms a spherical shape
In these and other observances, liquid droplets behave like small spherical
balloons filled with the liquid, and the surface of the liquid acts like a
stretched elastic membrane under tension. The pulling force that causes this
tension acts parallel to the surface and is due to the attractive forces between
the molecules of the liquid. The magnitude of this force per unit length is
called surface tension ss and is usually expressed in the unit N/m (or lbf/ft in
English units). This effect is also called surface energy and is expressed in the
equivalent unit of N · m/m2 or J/m2. In this case, ss represents the stretching
work that needs to be done to increase the surface area of the liquid by a unit
To visualize how surface tension arises, we present a microscopic view in
Fig. 10–20 by considering two liquid molecules, one at the surface and one
deep within the liquid body. The attractive forces applied on the interior molecule by the surrounding molecules balance each other because of symmetry.
But the attractive forces acting on the surface molecule are not symmetric, and
the attractive forces applied by the gas molecules above are usually very
small. Therefore, there is a net attractive force acting on the molecule at the
surface of the liquid, which tends to pull the molecules on the surface toward
the interior of the liquid. This force is balanced by the repulsive forces from A molecule
on the surface A molecule
liquid FIGURE 10–20
Attractive forces acting on a liquid
molecule at the surface and
deep inside the liquid. cen54261_ch10.qxd 12/2/03 10:55 AM Page 476 476
FUNDAMENTALS OF THERMAL-FLUID SCIENCES Rigid wire frame
Surface of film Movable
∆x the molecules below the surface that are being compressed. The resulting
compression effect causes the liquid to minimize its surface area. This is the
reason for the tendency of the liquid droplets to attain a spherical shape, which
has the minimum surface area for a given volume.
You also may have observed, with amusement, that some insects can land
on water (even walk on water) and that small steel needles can float on water.
These are again made possible by surface tension that balances the weights of
To understand the surface tension effect better, consider a liquid film (such
as the film of a soap bubble) suspended on a U-shaped wire frame with a movable side (Fig. 10–21). Normally, the liquid film tends to pull the movable
wire inward in order to minimize its surface area. A force F needs to be applied on the movable wire in the opposite direction to balance this pulling effect. The thin film in the device has two surfaces (the top and bottom surfaces)
exposed to air, and thus the length along which the tension acts in this case is
2b. Then a force balance on the movable wire gives F 2bss, and thus the
surface tension can be expressed as x ss σs
Liquid film σs TABLE 10–3
Surface tension of some
fluids in air at 1 atm and 20 C
(unless otherwise stated) Water:
SAE 30 oil
Blood, 37 C
Kerosene (10–12) F
Wire FIGURE 10–21
Stretching a liquid film with a
U-shaped wire, and the forces acting
on the movable wire of length b. Fluid F
2b Surface tension
0.028 *Multiply by 0.06852 to convert to lbf/ft. Note that for b 0.5 m, the force F measured (in N) is simply the surface
tension in N/m. An apparatus of this kind with sufficient precision can be used
to measure the surface tension of various fluids.
In the U-shaped wire, the force F remains constant as the movable wire is
pulled to stretch the film and increase its surface area. When the movable wire
is pulled a distance x, the surface area increases by A 2b x, and the
work done W during this stretching process is
W Force Distance Fx 2bss x ss A since the force remains constant in this case. This result can also be interpreted as the surface energy of the film is increased by an amount ss A
during this stretching process, which is consistent with the alternative interpretation of ss as surface energy. This is similar to a rubber band having more
potential (elastic) energy after it is stretched further. In the case of liquid film,
the work is used to move liquid molecules from the interior parts to the surface against the attraction forces of other molecules. Therefore, surface tension also can be defined as the work done per unit increase in the surface area
of the liquid.
The surface tension varies greatly from substance to substance, and with
temperature for a given substance, as shown in Table 10–3. At 20 C, for example, the surface tension is 0.073 N/m for water and 0.440 N/m for mercury
surrounded by atmospheric air. The very high surface tension also explains
why mercury droplets form spherical balls that can be rolled like a solid ball
on a surface without wetting the surface. The surface tension of a liquid, in
general, decreases with temperature and becomes zero at the critical point
(and thus there is no distinct liquid–vapor interface at temperatures above the
critical point). The effect of pressure on surface tension is usually negligible. cen54261_ch10.qxd 12/2/03 10:55 AM Page 477 477
CHAPTER 10 The surface tension of a substance can be changed considerably by impurities. Therefore, certain chemicals, called surfactants, can be added to a liquid
to decrease its surface tension. For example, soaps and detergents lower the
surface tension of water and enable it to penetrate through the small openings
between fibers for more effective washing. But this also means that devices
whose operation depends on surface tension (such as heat pipes) can be destroyed by the presence of impurities due to poor workmanship.
We speak of surface tension for liquids only at liquid–liquid or liquid–gas
interfaces. Therefore, it is important to specify the adjacent liquid or gas when
specifying surface tension. Also, surface tension determines the size of the
liquid droplets that form. A droplet that keeps growing by the addition of more
mass will break down when the surface tension can no longer hold it together.
This is like a balloon that will burst while being inflated when the pressure inside rises above the strength of the balloon material.
A curved interface indicates a pressure difference (or “pressure jump”)
across the interface with pressure being higher on the concave side. The excess pressure P inside a droplet or bubble above the atmospheric pressure,
for example, can be determined by considering the free-body diagram of half
a droplet or bubble (Fig. 10–22). Noting that surface tension acts along the circumference and the pressure acts on the area, horizontal force balances for the
droplet and the bubble give
Droplet: (2pR)ss (pR2) Pdroplet → Pdroplet Pi Po 2ss
R 2(2pR)ss (pR2) Pbubble → Pbubble Pi Po 4ss
R (10–14) (π R2)∆Pdroplet (10–13) Bubble: (2π R)σs (a) Half a droplet
2(2π R)σs where Pi and Po are the pressures inside and outside the droplet or bubble,
respectively. When the droplet or bubble is in the atmosphere, Po is simply
atmospheric pressure. The factor 2 in the force balance for the bubble is due
to the bubble consisting of a film with two surfaces (inner and outer surfaces)
and thus two circumferences in the cross section.
The excess pressure in a droplet (or bubble) also can be determined by
considering a differential increase in the radius of the droplet due to the
addition of a differential amount of mass and interpreting the surface tension
as the increase in the surface energy per unit area. Then the increase in the
surface energy of the droplet during this differential expansion process
dWsurface ss dA ss d(4pR2) 8pRss dR The expansion work done during this differential process is determined by
multiplying the force by distance to obtain
dWexpansion Force Distance F dR ( PA) dR 4pR2 P dR Equating the two expressions above gives Pdroplet 2ss /R, which is the same
relation obtained before and given in Eq. 10–13. Note that the excess pressure
in a droplet or bubble is inversely proportional to the radius. (π R2)∆Pbubble (b) Half a bubble FIGURE 10–22
The free-body diagram of half a
droplet and half a bubble. cen54261_ch10.qxd 12/2/03 10:55 AM Page 478 478
FUNDAMENTALS OF THERMAL-FLUID SCIENCES Capillary Effect φ
Water Mercury (a) Wetting
fluid (b) Nonwetting
fluid FIGURE 10–23
The contact angle for wetting
and nonwetting fluids. FIGURE 10–24
The meniscus of colored water in a
4-mm inner diameter glass tube. Note
that the edge of the meniscus meets
the wall of the capillary tube at a very
small contact angle. (Photo by
Gabrielle Tremblay, Pennsylvania
State University.) Another interesting consequence of surface tension is the capillary effect,
which is the rise or fall of a liquid in a small-diameter tube inserted into the
liquid. Such narrow tubes or confined flow channels are called capillaries.
The rise of kerosene through a cotton wick inserted into the reservoir of a
kerosene lamp is due to this effect. The capillary effect is also partially responsible for the rise of water to the top of tall trees. The curved free surface
of a liquid in a capillary tube is called the meniscus.
It is commonly observed that water in a glass container curves up slightly at
the edges where it touches the glass surface; but the opposite occurs for mercury: it curves down at the edges (Fig. 10–23). This effect is usually expressed
by saying that water wets the glass (by sticking to it) while mercury does not.
The strength of the capillary effect is quantified by the contact (or wetting)
angle f, defined as the angle that the tangent to the liquid surface makes with
the solid surface at the point of contact. The surface tension force acts along
this tangent line toward the solid surface. A liquid is said to wet the surface
when f 90º and not to wet the surface when f 90º. In atmospheric air,
the contact angle of water (and most other organic liquids) with glass is nearly
zero, f 0º (Fig. 10–24). Therefore, the surface tension force acts upward on
water in a glass tube along the circumference, tending to pull the water up. As
a result, water rises in the tube until the weight of the liquid in the tube above
the liquid level of the reservoir balances the surface tension force. The contact
angle is 130º for mercury–glass and 26º for kerosene–glass in air. Note that
the contact angle, in general, is different in different environments (such as
another gas or liquid in place of air).
The phenomenon of capillary effect can be explained microscopically by
considering cohesive forces (the forces between like molecules, like water)
and adhesive forces (the forces between dislike molecules, like water and
glass). The liquid molecules at the solid–liquid interface are subjected to both
cohesive forces by other liquid molecules and adhesive forces by the molecules of the solid. The relative magnitudes of these forces determine whether
a liquid wets a solid surface or not. Obviously, the water molecules are more
strongly attracted to the glass molecules than they are to other water molecules, and thus water tends to rise along the glass surface. The opposite occurs
for mercury, which causes the liquid surface near the glass wall to be suppressed (Fig. 10–25).
The magnitude of the capillary rise in a circular tube can be determined
from a force balance on the cylindrical liquid column of height h in the tube
(Fig. 10–26). The bottom of the liquid column is at the same level as the free
surface of the reservoir, and thus the pressure there must be atmospheric
pressure. This balances the atmospheric pressure acting at the top surface, and
thus these two effects cancel each other. The weight of the liquid column is
W mg rVg rg(pR2h) Equating the vertical component of the surface tension force to the weight
W Fsurface → rg(pR2h) 2pRss cos f cen54261_ch10.qxd 12/2/03 10:55 AM Page 479 479
CHAPTER 10 Solving for h gives the capillary rise to be
Capillary rise: h 2ss
rgR Meniscus (R constant) (10–15) This relation is also valid for nonwetting liquids (such as mercury in glass)
and gives the capillary drop. In this case f 90º and thus cos f 0, which
makes h negative. Therefore, a negative value of capillary rise corresponds to
a capillary drop (Fig. 10–25).
Note that the capillary rise is inversely proportional to the radius of the tube.
Therefore, the thinner the tube is, the greater the rise (or fall) of the liquid in
the tube. In practice, the capillary effect is usually negligible in tubes whose
diameter is greater than 1 cm. When pressure measurements are made using
manometers and barometers, it is important to use sufficiently large tubes to
minimize the capillary effect. The capillary rise is also inversely proportional
to the density of the liquid, as expected. Therefore, lighter liquids experience
greater capillary rises. Finally, it should be kept in mind that Eq. 10–15 is derived for constant diameter tubes and should not be used for tubes of variable
cross section. h Meniscus
h Water Mercury FIGURE 10–25
The capillary rise of water and the
capillary fall of mercury in a
small-diameter glass tube.
φ 2π Rσs h
W Liquid 2R EXAMPLE 10–4 The Capillary Rise of Water in a Tube A 0.6-mm-diameter glass tube is inserted into water at 20 C in a cup. Determine the capillary rise of water in the tube (Fig. 10–27). SOLUTION The rise of water in a slender tube as a result of the capillary effect
is to be determined.
Assumptions 1 There are no impurities in the water and no contamination on
the surfaces of the glass tube. 2 The experiment is conducted in atmospheric
Properties The surface tension of water at 20 C is 0.073 N/m (Table 10–3).
The contact angle of water with glass is 0 (from preceding text). We take the
density of liquid water to be 1000 kg/m3.
Analysis The capillary rise is determined directly from Eq. 10–15 by substituting the given values, yielding h 2ss
0.050 m 2(0.073 N/m)
(1000 kg/m )(9.81 m/s2)(0.3
3 1kg m /s2
b cos 0
3 a 5.0 cm FIGURE 10–26
The forces acting on a liquid column
that has risen in a tube due to
the capillary effect.
2π Rσs h Air
Water W FIGURE 10–27
Schematic for Example 10–4. Therefore, water rises in the tube 5 cm above the liquid level in the cup.
Discussion Note that if the tube diameter were 1 cm, the capillary rise would
be 0.3 mm, which is hardly noticeable to the eye. Actually, the capillary rise in
a large-diameter tube occurs only at the rim. The center does not rise at all.
Therefore, the capillary effect can be ignored for large-diameter tubes. SUMMARY
In this chapter the basic concepts of fluid mechanics are introduced and discussed. Fluid mechanics is the science that deals with the behavior of fluids at rest or in motion, and the interaction of fluids with solids or other fluids at the boundaries. cen54261_ch10.qxd 12/4/03 8:42 AM Page 480 480
FUNDAMENTALS OF THERMAL-FLUID SCIENCES The flow of an unbounded fluid over a surface is external
flow, and the flow in a pipe or duct is internal flow if the fluid
is completely bounded by solid surfaces. A fluid flow is classified as being compressible or incompressible, depending on the
density variation of the fluid during flow. The densities of liquids are essentially constant, and thus the flow of liquids is typically incompressible. The term steady implies no change with
time. The opposite of steady is unsteady, or transient. The term
uniform implies no change with location over a specified region. A flow is said to be one-dimensional when the velocity
changes in one dimension only. A fluid in direct contact with a
solid surface sticks to the surface and there is no slip. This is
known as the no-slip condition, and it is due to the viscosity of
At a given temperature, the pressure at which a pure substance changes phase is called the saturation pressure. For
phase-change processes between the liquid and vapor phases of
a pure substance, the saturation pressure is commonly called
the vapor pressure Pυ .
The viscosity of a fluid is a measure of its “stickiness” or “resistance to deformation.” The tangential force per unit area is
called shear stress, and is expressed for simple shear flow between plates (one-dimensional flow) as
t m du
dy where m is the dynamic (or absolute) viscosity of the fluid, u is
the velocity component in the flow direction, and y is the direction normal to flow direction. The fluids that obey this linear relationship are called Newtonian fluids. The ratio of
dynamic viscosity to density is called the kinematic viscosity, υ. For liquids, both the dynamic and kinematic viscosities are essentially independent of pressure. For gases, this is also the
case for dynamic viscosity, but not for kinematic viscosity
since the density of a gas is proportional to its pressure.
The pulling effect on the liquid molecules at an interface
caused by the attractive forces of molecules per unit length is
called surface tension ss. The excess pressure P inside a
spherical droplet or bubble is given by
Pdroplet Pi Po 2ss
R Pbubble Pi Po 4 ss
R and where Pi and Po are the pressures inside and outside the droplet
or bubble. The rise or fall of a liquid in a small-diameter tube
inserted into the liquid due to surface tension is called the capillary effect. The strength of the capillary effect is quantified
by the contact angle f, defined as the angle that the tangent to
the liquid surface makes with the solid surface at the point of
contact. A liquid is said to wet the surface when f 90 , and
not to wet the surface when f 90 . The capillary rise or drop
is given by
rgR The capillary rise is inversely proportional to the radius of the
tube, and is negligible for tubes whose diameter is larger than
about 1 cm. REFERENCES AND SUGGESTED READING
1. Y. A. Cengel and M. A. Boles. Thermodynamics: An
Engineering Approach. 4th ed. New York: McGraw-Hill,
2002. 7. L. Trefethen. “Surface Tension in Fluid Mechanics.” In
Illustrated Experiments in Fluid Mechanics. Cambridge,
MA: MIT Press, 1972. 2. C. T. Crowe, J. A. Roberson, and D. F. Elger. Engineering
Fluid Mechanics. 7th ed. New York: Wiley, 2001. 8. The U.S. Standard Atmosphere. Washington, DC: U.S.
Government Printing Office, 1976. 3. R. W. Fox and A. T. McDonald. Introduction to Fluid
Mechanics. 5th ed. New York: Wiley, 1999. 9. M. Van Dyke. An Album of Fluid Motion. Stanford, CA:
Parabolic Press, 1982. 4. D. C. Giancoli. Physics. 3rd ed. Upper Saddle River, NJ:
Prentice Hall, 1991.
5. M. C. Potter and D. C. Wiggert. Mechanics of Fluids.
2nd ed. Upper Saddle River, NJ: Prentice Hall, 1997.
6. Y. S. Touloukian, S. C. Saxena, and P. Hestermans.
Thermophysical Properties of Matter, The TPRC Data
Series, Vol. 11, Viscosity. New York: Plenum, 1975. 10. F. M. White. Fluid Mechanics. 5th ed. New York:
11. C. L. Yaws, X. Lin, and L. Bu. “Calculate Viscosities for
355 Compounds. An Equation Can be Used to Calculate
Liquid Viscosity as a Function of Temperature.” Chemical
Engineering, 101, no. 4 (April 1994), 1110–1128.
12. C. L. Yaws. Handbook of Viscosity. 3 Vols. Houston, TX:
Gulf Publishing, 1994. cen54261_ch10.qxd 1/8/04 8:12 AM Page 481 481
CHAPTER 10 PROBLEMS*
Classification of Fluid Flows, Vapor Pressure, and
10–1C Define internal, external, and open-channel flows. 10–2C Define incompressible flow and incompressible fluid.
Must the flow of a compressible fluid necessarily be treated as
10–13C What is viscosity? What is the cause of it in liquids and in gases? Do liquids or gases have higher dynamic
fluid? What is a Newtonian fluid? Is water a Newtonian 10–4C What is forced flow? How does it differ from natural
flow? Is flow caused by wind forced or natural flow? 10–15C Consider two identical small glass balls dropped
into two identical containers, one filled with water and the
other with oil. Which ball will reach the bottom of the container first? Why? 10–5C What is vapor pressure? How is it related to saturation pressure? 10–16C How does the dynamic viscosity of (a) liquids and
(b) gases vary with temperature? 10–3C What is the no-slip condition? What causes it? 10–6C Does water boil at higher temperatures at higher pressures? Explain.
10–7C If the pressure of a substance is increased during a
boiling process, will the temperature also increase or will it remain constant? Why?
10–8C What is cavitation? What causes it?
10–9 In a piping system, the water temperature remains under 40 C. Determine the minimum pressure allowed in the system to avoid cavitation.
10–10 The analysis of a propeller that operates in water at
20 C shows that the pressure at the tips of the propeller drops
to 2 kPa at high speeds. Determine if there is a danger of cavitation for this propeller.
10–11E The analysis of a propeller that operates in water at
70 F shows that the pressure at the tips of the propeller drops
to 0.1 psia at high speeds. Determine if there is a danger of cavitation for this propeller.
10–12 A pump is used to transport water to a higher reservoir. If the water temperature is 25 C, determine the lowest
pressure that can exist in the pump without cavitation. 10–17C How does the kinematic viscosity of (a) liquids and
(b) gases vary with temperature?
10–18 A 50-cm 30-cm 20-cm block weighing 150 N is
to be moved at a constant velocity of 0.8 m/s on an inclined
surface with a friction coefficient of 0.27. (a) Determine the
force F that needs to be applied in the horizontal direction.
(b) If a 0.4-mm-thick oil film with a dynamic viscosity of
0.012 Pa s is applied between the block and inclined surface,
determine the percent reduction in the required force.
= 0.8 m/s 50 cm
30 cm F 20º
150 N FIGURE P10–18
10–19 Consider the flow of a fluid with viscosity m though a
circular pipe. The velocity profile in the pipe is given as u(r)
umax(1 r n/R n), where umax is maximum flow velocity, which
occurs at the centerline; r is the radial distance from the centerline; and u(r) is the flow velocity at any position r. Develop
a relation for the drag force exerted on the pipe wall by the
fluid in the flow direction per unit length of the pipe.
u(r) = umax (1 – rn/Rn)
R *Problems designated by a “C” are concept questions, and
students are encouraged to answer them all. Problems designated
by an “E” are in English units, and the SI users can ignore them.
Problems with a CD-EES icon
are solved using EES, and
complete solutions together with parametric studies are included
on the enclosed CD. Problems with a computer-EES icon
comprehensive in nature, and are intended to be solved with a
computer, preferably using the EES software that accompanies
this text. r umax 0 FIGURE P10–19
10–20 A thin 20-cm 20-cm flat plate is pulled at 1 m/s horizontally through a 3.6-mm-thick oil layer sandwiched between
two plates, one stationary and the other moving at a constant cen54261_ch10.qxd 2/12/04 3:54 PM Page 482 482
FUNDAMENTALS OF THERMAL-FLUID SCIENCES velocity of 0.3 m/s, as shown in the figure. The dynamic viscosity of oil is 0.027 Pa s. Assuming the velocity in each oil layer
to vary linearly, (a) plot the velocity profile and find the location
where the oil velocity is zero and (b) determine the force that
needs to be applied on the plate to maintain this motion.
h1 = 1 mm = 1 m/s h2 = 2.6 mm F
w = 0.3 m/s Moving wall FIGURE P10–20
10–21 A frustum-shaped body is rotating at a constant angular speed of 200 rad/s in a container filled with SAE 10W oil at
20 C (m 0.1 Pa s), as shown in the figure. If the thickness
of the oil film on all sides is 1.2 mm, determine the power required to maintain this motion. Also determine the reduction in
the required power input when the oil temperature rises to 80 C
(m 0.0078 Pa s). 10–23 Reconsider Prob. 10–22. Using EES (or other)
software, investigate the effect of oil film thickness on the torque transmitted. Let the film thickness vary from
0.1 mm to 10 mm. Plot your results, and state your conclusions.
10–24 The viscosity of some fluids changes when a strong
electric field is applied on them. This phenomenon is known as
the electrorheological (ER) effect, and fluids that exhibit such
behavior are known as ER fluids. The Bingham plastic model for
shear stress, which is expressed as t ty m(du/dy) is widely
used to describe ER fluid behavior because of its simplicity. One
of the most promising applications of ER fluids is the ER clutch.
A typical multidisk ER clutch consists of several equally spaced
steel disks of inner radius R1 and outer radius R2, N of them attached to the input shaft. The gap h between the parallel disks is
filled with a viscous fluid. (a) Find a relationship for the torque
generated by the clutch when the output shaft is stationary
and (b) calculate the torque for an ER clutch with N 11 for
R1 50 mm, R2 200 mm, and n 2400 rpm if the fluid is
SAE 10 with m 0.1 Pa s, ty 2.5 kPa, and h 1.2 mm.
Answer: (b) 2060 N m h = 1.2 mm
Shell R2 Case
SAE 10W oil D = 12 cm
z L = 12 cm d = 4 cm 10–22 The clutch system shown in the figure is used to transmit torque through a 3-mm-thick oil film with m
N s/m2 between two identical 30-cm-diameter disks. When
the driving shaft rotates at a speed of 1450 rpm, the driven
shaft is observed to rotate at 1398 rpm. Assuming a linear velocity profile for the oil film, determine the transmitted torque. 30 cm Output shaft Plates mounted
Plates mounted on shell
on input shaft
Variable magnetic field FIGURE P10–24
r FIGURE P10–21 Driving
shaft R1 Driven
SAE 30W oil FIGURE P10–22 10–25 The viscosity of some fluids, called magnetorheological
(MR) fluids, changes when a magnetic field is applied. Such fluids involve micron-sized magnetizable particles suspended in an
appropriate carrier liquid, and are suitable for use in controllable
hydraulic clutches. See Fig. P10–24. The MR fluids can have
much higher viscosities than the ER fluids, and they often exhibit shear-thinning behavior in which the viscosity of the fluid
decreases as the applied shear force increases. This behavior is
also known as pseudoplastic behavior, and can be successfully
represented by Herschel–Bulkley constitutive model expressed
as t ty K(du/dy)m. Here t is the shear stress applied, ty is
the yield stress, K is the consistency index, and m is the power
index. For a Herschel–Bulkley fluid with ty 900 Pa, K 58
Pa s m , and m
0.82, (a) find a relationship for the torque
transmitted by an MR clutch for N plates attached to the input
shaft when the input shaft is rotating at an angular speed of ω
while the output shaft is stationary and (b) calculate the torque
transmitted by such a clutch with N 11 plates for R1 50 mm,
R2 200 mm, n 2400 rpm, and h 1.2 mm.
10–26 The viscosity of a fluid is to be measured by a viscometer constructed of two 75-cm-long concentric cylinders.
The outer diameter of the inner cylinder is 15 cm, and the gap
between the two cylinders is 0.12 cm. The inner cylinder is cen54261_ch10.qxd 2/12/04 3:54 PM Page 483 483
CHAPTER 10 rotated at 200 rpm, and the torque is measured to be 0.8 N · m.
Determine the viscosity of the fluid.
10–27E The viscosity of a fluid is to be measured by a viscometer constructed of two 3-ft-long concentric cylinders. The
inner diameter of the outer cylinder is 6 in, and the gap between the two cylinders is 0.05 in. The outer cylinder is rotated
at 250 rpm, and the torque is measured to be 1.2 lbf · ft. Determine the viscosity of the fluid. 10–35E A 0.03-in-diameter glass tube is inserted into
kerosene at 68 F. The contact angle of kerosene with a glass
surface is 26 . Determine the capillary rise of kerosene in the
tube. Answer: 0.65 in
0.03 in h Answer: 0.000648 lbs s/ft2
200 rpm Kerosene 0.12 cm
Fluid FIGURE P10–35E
cylinder 10–36 A 1.9-mm-diameter tube is inserted into an unknown
liquid whose density is 960 kg/m3, and it is observed that the
liquid rises 5 mm in the tube, making a contact angle of 15 .
Determine the surface tension of the liquid.
10–37 FIGURE P10–26
10–28 In regions far from the entrance, fluid flow through a
circular pipe is one-dimensional, and the velocity profile for
laminar flow is given by u(r) umax(1 r 2/R2) where R is the
radius of the pipe, r is the radial distance from the center of the
pipe, and umax is the maximum flow velocity, which occurs at
the center. Obtain (a) a relation for the drag force applied by the
fluid on a section of the pipe of length L and (b) the value of the
drag force for water flow at 20 C with R 0.08 m, L 15 m,
umax 3 m/s, and m 0.0010 kg/m s. Determine the gage pressure inside a soap bubble of diameter (a) 0.2 cm and (b) 5 cm at 20°C. 10–38 Nutrients dissolved in water are carried to upper parts
of plants by tiny tubes partly because of the capillary effect.
Determine how high the water solution will rise in a tree in a
0.005-mm-diameter tube as a result of the capillary effect.
Treat the solution as water at 20°C with a contact angle of 15 .
Answer: 5.75 m 2
umax 1 – r 2 ( rR
o R ) umax FIGURE P10–28
10–29 Repeat Prob. 10–28 for umax 5 m/s. Answer: (b) 0.942 N Surface Tension and Capillary Effect
10–30C What is surface tension? What is it caused by? Why
is the surface tension also called surface energy?
10–31C Consider a soap bubble. Is the pressure inside the
bubble higher or lower than the pressure outside?
10–32C What is the capillary effect? What is it caused by?
How is it affected by the contact angle?
10–33C A small-diameter tube is inserted into a liquid whose
contact angle is 110 . Will the level of liquid in the tube rise or
10–34C Is the capillary rise greater in small- or largediameter tubes? 0.005 mm
Water solution FIGURE P10–38
10–39 The surface tension of a liquid is to be measured using
a liquid film suspended on a U-shaped wire frame with an
8-cm-long movable side. If the force needed to move the wire
is 0.012 N, determine the surface tension of this liquid in air. cen54261_ch10.qxd 1/13/04 1:47 PM Page 484 484
FUNDAMENTALS OF THERMAL-FLUID SCIENCES 10–40 Contrary to what you might expect, a solid steel ball
can float on water due to the surface tension effect. Determine
the maximum diameter of a steel ball that would float on water
at 20 C. What would your answer be for an aluminum ball?
Take the densities of steel and aluminum balls to be 7800
kg/m3 and 2700 kg/m3, respectively. Review Problems
10–41E The pressure on the suction side of pumps is typically low, and the surfaces on that side of the pump are susceptible to cavitation, especially at high fluid temperatures. If the
minimum pressure on the suction side of a water pump is 0.95
psia absolute, determine the maximum water temperature to
avoid the danger of cavitation.
10–42 A closed tank is partially filled with water at 60 C. If
the air above the water is completely evacuated, determine the
absolute pressure in the evacuated space. Assume the temperature to remain constant.
10–43 The variation of the dynamic viscosity of water
with absolute temperature is given as
373.15 10–45 Some non-Newtonian fluids behave as a Bingham plastic for which shear stress can be expressed as t ty m(du/dr).
For laminar flow of a Bingham plastic in a horizontal pipe of
radius R, the velocity profile is given as u(r) ( P/4mL)(r 2
R2) (ty /m)(r R), where P/L is the constant pressure drop
along the pipe per unit length, m is the dynamic viscosity, r is the
radial distance from the centerline, and ty is the yield stress of
Bingham plastic. Determine (a) the shear stress at the pipe wall
and (b) the drag force acting on a pipe section of length L.
10–46 In some damping systems, a circular disk immersed
in oil is used as a damper, as shown in the figure. Show
that the damping torque is proportional to angular speed in
Cv where C
accordance with the relation Tdamping
0.5pm(1/a 1/b)R4. Assume linear velocity profiles on both
sides of the disk and neglect the tip effects. R
a m (Pa s)
10 3 b 3 Disk Damping oil 3
4 FIGURE P10–46 4 10–47E A 0.9-in-diameter glass tube is inserted into mercury, which makes a contact angle of 140 with glass. Determine the capillary drop of mercury in the tube at 68 F. 4
4 Answer: 0.0175 in Using tabulated data, develop a relation for viscosity in the form
of m m(T ) A BT CT 2 DT 3 ET 4. Using the relation
developed, predict the dynamic viscosity of water at 50 C at
which the reported value is 5.468 10 4 Pa s. Compare your
result with the results of Andrade’s equation, which is given in
the form of m D eB/T, where D and B are constants whose
values are to be determined using the viscosity data given.
10–44 Consider laminar flow of a Newtonian fluid of viscosity m between two parallel plates. The flow is one-dimensional,
and the velocity profile is given as u(y) 4umax[y/h (y/h)2],
where y is the vertical coordinate from the bottom surface, h is
the distance between the two plates, and umax is the maximum
flow velocity that occurs at midplane. Develop a relation for
the drag force exerted on both plates by the fluid in the flow direction per unit area of the plates.
u(y) = 4umax [y/h – (y/h)2] y umax 0 FIGURE P10–44 h 10–48 Derive a relation for the capillary rise of a liquid between two large parallel plates a distance t apart inserted into
the liquid vertically. Take the contact angle to be f.
10–49 Consider a 30-cm-long journal bearing that is lubricated with oil whose viscosity is 0.1 kg/m s at 20 C at the beginning of operation and 0.008 kg/m s at the anticipated
steady operating temperature of 80 C. The diameter of the
shaft is 8 cm, and the average gap between the shaft and the
journal is 0.08 cm. Determine the torque needed to overcome
the bearing friction initially and during steady operation when
the shaft is rotated at 500 rpm. Design and Essay Problems
10–50 Design an experiment to measure the viscosity of liquids using a vertical funnel with a cylindrical reservoir of
height h and a narrow flow section of diameter D and length L.
Making appropriate assumptions, obtain a relation for viscosity in terms of easily measurable quantities such as density and
volume flow rate.
10–51 Write an essay on the rise of the fluid to the top of the
trees by the capillary and other effects.
10–52 Write an essay on the oils used in car engines in different seasons and their viscosities. ...
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