Fall 2011 Homework 15 Solutions

Fall 2011 Homework 15 Solutions - Physics 21 Fall 2011...

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Unformatted text preview: Physics 21 Fall, 2011 Solution to HW-15 28-32 A solid conductor with radius a is supported by in- sulating disks on the axis of a conducting tube with inner radius b and outer radius c . The central conductor and tube carry equal currents I in opposite directions. The currents are distributed uniformly over the cross sections of each con- ductor. (a) Derive an expression for the magnitude of the magnetic field at points outside the central, solid conductor, but inside the tube ( a < r < b ). (b) Derive an expression for the magnitude of the magnetic field at points outside the tube ( r > c ). (a) This problem is best answered with Ampere’s Law contintegraldisplay B · d l = μ I encl Chose a circular line integral path with radius r between the center and outer conductor, then by symmetry we expect the value of B to be constant around the path. The only current enclosed is the current I in the center conductor. 2 πrB inside = μ I Solving for B, B inside = μ I 2 πr = ( 2 × 10- 7 ) I r (b) Taking a similar approach for this problem, choose a current loop with radius...
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This note was uploaded on 12/18/2011 for the course PHYS 021 taught by Professor Hickman during the Spring '08 term at Lehigh University .

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Fall 2011 Homework 15 Solutions - Physics 21 Fall 2011...

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