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Unformatted text preview: Physics 21 Fall, 2011 Solution to HW12 2736 A straight, vertical wire carries a current of I = 1 . 19 A downward in a region between the poles of a large superconducting electromagnet, where the magnetic field B has a magnitude of B = 0.591 T and is horizontal. What are the magnitude and direction of the magnetic force on a section of the wire with a length of l = 1 . 00 cm that is in this uniform magnetic field, if the magnetic field direction is (a) east, (b) south, (c) 34 ◦ south of west? The diagram shows the view looking down in the direction of the current, for an arbitrary orientation of B in the hori zontal plane: N E S W B F mag I We use the right hand rule to evaluate the magnetic force F mag = I l × B , where l is a vector of length l , the length of the wire section, that points in the direction of the current. One can see that for any horizontal B , the magnetic force will also be horizontal, and its direction will be 90 ◦ clockwise from B . (a) For B pointing east, the magnitude of F mag is F mag = IlB = (1 . 19 A)(0 . 010 m)(0 . 591 T) = 7 . 03 mN and the direction is south. (b) For B pointing south, F mag is the same as in part (a), and the direction of F mag is west....
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This note was uploaded on 12/18/2011 for the course PHYS 021 taught by Professor Hickman during the Spring '08 term at Lehigh University .
 Spring '08
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