Unformatted text preview: ΒΆ 2 = β 11134 38 = β 293 Γ 38 38 = β 293 β 38 . 12. Let P be a point inside the triangle ABC . Then the line through P and parallel to AC will meet the segments AB and BC in D and E , respectively. Then P = (1r ) D + r E , < r < 1; D = (1s ) B + s A , < s < 1; E = (1t ) B + t C , < t < 1 . Hence P = (1r ) { (1s ) B + s A } + r { (1t ) B + t C } = (1r ) s A + { (1r )(1s ) + r (1t ) } B + rt C = Ξ± A + Ξ² B + Ξ³ C , 92...
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 Fall '10
 Dreibelbis
 position vector, arbitrary point, direction vector

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