Pre-Calculus Homework Solutions 6

# Pre-Calculus Homework Solutions 6 - 22 y 8 30 H x 4 0 8 4...

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Unformatted text preview: 22. y 8 30. H x 4 0 8 4 G8 (GH)2 (GH)2 (GH)2 GH 23. d X ¬3 x1)2 (y2 (9 0)2 ¬ (12 ¬ 225 d ¬ (x2 x1)2 ¬ (7 ¬ 16 ¬5.7 3)2 16 d ¬ (x2 x1)2 ST ST ST ST 26. ¬ [6 ¬ 92 ¬ 90 ¬9.5 d ¬ (x2 x1)2 122 92 5)2 (9 ¬1 42 42 37. 32 2)2 ¬ (5 ¬ 9 16 ¬5 (y2 ¬1 x2 y1 , 2 y2 2 (y2 (7 25 y1)2 ¬ 12 4 8 , 2 2 2 ¬(10, 3) 38. x1 x2 y1 , 2 y2 2 ¬ 9 2 17 , 5 2 4 ¬ 26 , 9 22 ¬(13, 4.5) y1)2 x1 x2 y1 y2 39. 32 , 2 42 2 ( 9) ¬ 11 ¬ 3)2 NP NP NP NP ¬ [3 ¬ 52 ¬ 61 ¬7.8 ( 2)]2 [4 ( 2)]2 62 25 36 d ¬ (x2 x1)2 QR QR QR QR 29. d XY XY XY YZ YZ YZ XZ XZ XZ XY ¬ [1 ¬ 62 ¬ 40 ¬6.3 ¬ (x2 ¬ [2 ¬ 42 ¬ 52 ¬ (4 ¬ 22 ¬8 ¬ [4 ¬ 62 ¬ 52 YZ ( 5)]2 (5 3)2 22 36 4 (y2 ( 2) 20 6 2,2 2 ¬( 10, x1)2 Chapter 1 x1 ¬ 20 , 6 22 ¬ (x2 28. 36. M y1)2 (y2 ¬ ¬2 2 15 d 27. ¬ 62 8 32 2 ¬ 21 or 0.5 ¬ 32 5 ¬2 2 34. M 35. M ( 3)]2 (5 2)2 32 81 9 UV UV UV ¬2 ¬ 5 or 2.5 2 y1)2 0)2 8 ¬5 5 0 33. M LM LM LM 25. ¬2 2 ¬ 10 2 32. M ¬ 26 JK JK 24. y1)2 (y2 ¬ 62 0 31. M (GX)2 (HX)2 (8)2 (15)2 289 17 ¬ (x2 x1)2 ¬ (x2 AB ¬ [ 5 ( 4)]2 [1 ( 3)]2 AB ¬ ( 1)2 42 1 16 AB ¬ 17 Because the figure is a square, the four sides are congruent. So the perimeter of the square is 4 17 16.5 units. 4 8 d , 4 2 3) y1)2 40. x1 x2 y1 , 2 y2 2 ¬ 4 2 8, 2 ( 6) 2 ¬ 12 , 24 2 ¬(6, 2) (y2 y1)2 41. x2 y1 , 2 y2 2 42. x1 x2 y1 , 2 y2 2 x1 43. S( 1, 5) 5)2 44 1 2 2 The x 52 2 4 6 The 8 ( 5.4) 2 1.1) ( 4) y1 3 , 2 2 ( 4) y 3 y 8 ¬1 5 ¬1 2 2 ¬x1 ( 4) 10 ¬y1 3 ¬x1 7 ¬y1 coordinates of R are (2, 7). x1 44. S( 2, 2) 52 8 17.3 units 1.4 2.6 3.2 , 2 1.2 2.2 ¬ 2, 2 ¬ ¬(0.6, ( 2)]2 [3 ( 1)]2 42 36 16 XZ ¬ 3.4 2 7.8 , 2.1 2 3.6 .7 ¬ 11.2 , 52 2 ¬(5.6, 2.85) x1)2 (y2 y1)2 ( 2)]2 [5 ( 1)]2 62 16 36 2)2 (3 ( 2)2 x1 x 2 y1 2 2 , 8 2 ¬1 2 ¬1 2 2 ¬x1 2 4 ¬y1 8 ¬x1 4 ¬y1 coordinates of R are ( 6, 4). ...
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## This note was uploaded on 12/19/2011 for the course MAC 1140 taught by Professor Dr.zhan during the Fall '10 term at UNF.

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