15
Chapter 1
Solve:
x
1
12
5
¬
180
2
x
x
5
¬
168
2
x
2
x
5
¬
168
x
5
¬
84
180
2
x
5
180
2
84 or 96
The measures of the angle and its supplement are
84 and 96.
Examine:
96
5
84
1
12
22. Explore:
The problem states that
m
/
1 is five
less than 4
?
m
/
2 and
/
1 and
/
2 form a linear
pair. So
m
/
1
1
m
/
2
5
180.
Plan:
Let
m
/
1
5
x
.
Solve:
m
/
1
1
m
/
2
5
¬
180
x
1
m
/
2
5
¬
180
4
?
m
/
2
2
5
1
m
/
2
5
¬
180
5
?
m
/
2
5
¬
185
m
/
2
5
¬
37
m
/
1
5
4
?
m
/
2
2
5
5
4(37)
2
5
5
148
2
5 or 143
Examine:
4(37)
2
5
0
¬
143
143
5
¬
143
/
1 and
/
2 are supplementary because
143
1
37
5
180.
23.
Always; the sum of two angles that each measure
less than 90° can never equal 180°, so if one angle
is acute the other must be obtuse.
24.
Always; complementary angles are angles whose
measures have a sum of 90°, so each angle must
measure less than 90°.
25.
Sometimes; for example, consider the following:
m
/
A
5
90
m
/
B
5
90
m
/
C
5
90
Then
m
/
A
1
m
/
B
5
180 and
m
/
B
1
m
/
C
5
180
and
m
/
A
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This note was uploaded on 12/19/2011 for the course MAC 1140 taught by Professor Dr.zhan during the Fall '10 term at UNF.
 Fall '10
 Dr.Zhan
 Calculus, PreCalculus

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