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37.
Sample answer:
38.
m
/
AKB
1
m
/
BKC
1
m
/
CKD
5
20
1
25
1
45 or
90, so
/
AKD
is a right angle and
A
w
K
w
'
K
w
D
w
.
m
/
DKE
1
m
/
EKF
5
60
1
30 or 90, so
/
DKF
is
a right angle and
K
w
D
w
'
K
w
F
w
.
m
/
EKF
1
m
/
FKG
5
30
1
60 or 90, so
/
EKG
is
a right angle and
K
w
E
w
'
K
w
G
w
.
39.
Because
/
WUT
and
/
TUV
are supplementary,
let
m
/
WUT
5
x
and
m
/
TUV
5
180
2
x
.A
bisector creates measures that are half of the
original angle, so
m
/
YUT
5
}
1
2
}
m
/
WUT
or
}
2
x
}
and
m
/
TUZ
5
}
1
2
}
m
/
TUV
or
}
180
2
2
x
}
. Then
m
/
YUZ
5
m
/
YUT
1
m
/
TUZ
or
}
2
x
}
1
}
180
2
2
x
}
. This sum simplifies to
}
18
2
0
}
or
90. Because
m
/
YUZ
5
90,
Y
w
U
w
'
U
w
Z
w
.
40.
Sample answer: The types of angles formed
depends on how the streets intersect. There may
be as few as two angles or many more if there are
more than two lines intersecting. Answers should
include the following.
• linear pairs, vertical angles, adjacent angles
• See students’ work.
41.
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This note was uploaded on 12/19/2011 for the course MAC 1140 taught by Professor Dr.zhan during the Fall '10 term at UNF.
 Fall '10
 Dr.Zhan
 Calculus, PreCalculus

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