Pre-Calculus Homework Solutions 14

# Pre-Calculus Homework Solutions 14 - 37. Sample answer: 52....

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37. Sample answer: 38. m / AKB 1 m / BKC 1 m / CKD 5 20 1 25 1 45 or 90, so / AKD is a right angle and A w K w ' K w D w . m / DKE 1 m / EKF 5 60 1 30 or 90, so / DKF is a right angle and K w D w ' K w F w . m / EKF 1 m / FKG 5 30 1 60 or 90, so / EKG is a right angle and K w E w ' K w G w . 39. Because / WUT and / TUV are supplementary, let m / WUT 5 x and m / TUV 5 180 2 x .A bisector creates measures that are half of the original angle, so m / YUT 5 } 1 2 } m / WUT or } 2 x } and m / TUZ 5 } 1 2 } m / TUV or } 180 2 2 x } . Then m / YUZ 5 m / YUT 1 m / TUZ or } 2 x } 1 } 180 2 2 x } . This sum simplifies to } 18 2 0 } or 90. Because m / YUZ 5 90, Y w U w ' U w Z w . 40. Sample answer: The types of angles formed depends on how the streets intersect. There may be as few as two angles or many more if there are more than two lines intersecting. Answers should include the following. • linear pairs, vertical angles, adjacent angles • See students’ work. 41.
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## This note was uploaded on 12/19/2011 for the course MAC 1140 taught by Professor Dr.zhan during the Fall '10 term at UNF.

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