Pre-Calculus Homework Solutions 19

Pre-Calculus Homework Solutions 19 - 37. XW bisects YXZ, so...

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37. XW ## $ bisects / YXZ , so / YXW > / WXZ and m / WXZ 5 ¬ } 1 2 } ? m / YXZ . m / WXZ 5 ¬ } 1 2 } ? m / YXZ 7 x 2 9 5 ¬ } 1 2 } (9 x 1 17) 7 x 2 9 5 ¬ } 9 2 } x 1 } 1 2 7 } 7 x 5 ¬ x 1 } 3 2 5 } } 5 2 } x 5 ¬ } 3 2 5 } x 5 ¬ 7 m / YXW 5 ¬ m / WXZ 5 ¬ 7 x 2 9 5 ¬ 7(7) 2 9 5 ¬ 40 38. / TWY , / WYX 39. / TWY , / XWY 40. T w W w ' W w Z w if m / TWZ 5 90. m / TWZ 5 ¬ 2 c 1 36 90 5 ¬ 2 c 1 36 54 5 ¬ 2 c 27 5 ¬ c 41. / ZWX 5 ¬ / ZWY 1 / YWX 90 5 ¬ 4 k 2 2 1 5 k 1 11 90 5 ¬ 9 k 1 9 81 5 ¬ 9 k 9 5 ¬ k 42. There are 4 sides, so the polygon is a quadrilateral. No line containing any of the sides will pass through the interior of the quadrilateral, so it is convex. The sides are congruent, and the angles are congruent, so it is regular. 43. The figure is not a polygon because there are sides that intersect more than two other sides. 44. There are 8 sides, so the polygon is an octagon. There is a side such that a line containing that side will pass through the interior of the octagon, so it is concave. The sides are not congruent, so the octagon is irregular.
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This note was uploaded on 12/19/2011 for the course MAC 1140 taught by Professor Dr.zhan during the Fall '10 term at UNF.

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