Pre-Calculus Homework Solutions 19

# Pre-Calculus Homework Solutions 19 - 37 XW bisects YXZ so...

This preview shows page 1. Sign up to view the full content.

37. XW ## \$ bisects / YXZ , so / YXW > / WXZ and m / WXZ 5 ¬ } 1 2 } ? m / YXZ . m / WXZ 5 ¬ } 1 2 } ? m / YXZ 7 x 2 9 5 ¬ } 1 2 } (9 x 1 17) 7 x 2 9 5 ¬ } 9 2 } x 1 } 1 2 7 } 7 x 5 ¬ x 1 } 3 2 5 } } 5 2 } x 5 ¬ } 3 2 5 } x 5 ¬ 7 m / YXW 5 ¬ m / WXZ 5 ¬ 7 x 2 9 5 ¬ 7(7) 2 9 5 ¬ 40 38. / TWY , / WYX 39. / TWY , / XWY 40. T w W w ' W w Z w if m / TWZ 5 90. m / TWZ 5 ¬ 2 c 1 36 90 5 ¬ 2 c 1 36 54 5 ¬ 2 c 27 5 ¬ c 41. / ZWX 5 ¬ / ZWY 1 / YWX 90 5 ¬ 4 k 2 2 1 5 k 1 11 90 5 ¬ 9 k 1 9 81 5 ¬ 9 k 9 5 ¬ k 42. There are 4 sides, so the polygon is a quadrilateral. No line containing any of the sides will pass through the interior of the quadrilateral, so it is convex. The sides are congruent, and the angles are congruent, so it is regular. 43. The figure is not a polygon because there are sides that intersect more than two other sides. 44. There are 8 sides, so the polygon is an octagon. There is a side such that a line containing that side will pass through the interior of the octagon, so it is concave. The sides are not congruent, so the octagon is irregular.
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Ask a homework question - tutors are online