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Pre-Calculus Homework Solutions 63

# Pre-Calculus Homework Solutions 63 - 30 Find the slope of n...

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30. Find the slope of n using (0, 6) and (8, 5). m ¬ ( ( y x 2 2 y x 1 1 ) ) ¬ 5 8 6 0 ¬ 1 8 y ¬ mx b y ¬ 1 8 x 6 31. Since the slope of line is 1 (from Exercise 28), the slope of a line perpendicular to it is 1. y y 1 ¬ m ( x x 1 ) y 6 ¬ 1[ x ( 1)] y 6 ¬ x 1 y ¬ x 5 32. Since the slope of line k is 3 (from Exercise 27), the slope of a line parallel to it is 3. y y 1 ¬ m ( x x 1 ) y 0 ¬ 3( x 7) y ¬ 3 x 21 33. Since the slope of line n is 1 8 (from Exercise 30), the slope of a line parallel to it is 1 8 . y y 1 ¬ m ( x x 1 ) y 0 ¬ 1 8 ( x 0) y ¬ 1 8 x 34. Since the slope of line m is 2 (from Exercise 29), the slope of a line perpendicular to it is 1 2 . y y 1 ¬ m ( x x 1 ) y ( 3) ¬ 1 2 [ x ( 3)] y 3 ¬ 2 1 x 3 2 y ¬ 1 2 x 9 2 35. y ¬ mx b y ¬ 3 x 5 36. y ¬ mx b y ¬ 0 x 6 y ¬ 6 37. m ¬ ( ( y x 2 2 y x 1 1 ) ) ¬ 3 0 0 5 ¬ 3 5 y ¬ mx b y ¬ 3 5 x 3 38. m ¬ ( ( y x 2 2 y x 1 1 ) ) ¬ 1 2 ( 4 1) ¬ 0 6 or 0 y y 1 ¬ m ( x x 1 ) y ( 1) ¬ 0( x 4) y 1 ¬ 0 y ¬ 1 39. m ¬ ( ( y x 2 2 y x 1 1 ) ) ¬ 10 6 ( ( 5 3 ) ) ¬ 15 3 or 1 5 y y 1 ¬ m ( x x 1 ) y ( 3) ¬ 1 5 [ x ( 5)] y 3 ¬ 1 5 x 1 y ¬ 1 5 x 4 40. m ¬ ( ( y x 2 2 y x 1 1 ) ) ¬ 0 1
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