8.x13y5¬63y5¬2x16y5¬2 }13}x12x13y5¬2143y5¬2x214y5¬2 }13}x2}134}First, write an equation of a line pperpendicularto the given lines. The slope of pis the opposite reciprocal of 2 }13}, or 3. Use the y-intercept of y52}13}x12, (0, 2), as one of the endpoints of theperpendicular segment.y2y15¬m(x2x1)y225¬3(x20)y225¬3x y5¬3x12Next, use a system of equations to determine thepoint of intersection of y}13}x2}134}and p.2 }13}x2}134}5¬3x122 }13}x23x5¬21 }134}2 }130}x5¬}230}x5¬22y5¬3(22)12y5¬24The point of intersection is (22,24).Then, use the Distance Formula to determine thedistance between (0, 2) and (22,24).d5¬Ï(x22wx1)21w(y22wy1)2w5¬Ï(222w0)21w(242w2)2w5¬Ï40w5¬2Ï10wThe distance between the lines is 2 Ï10w,orapproximately 6.32 units.9.1.Graph y}34}x1}14}and point P.Place thecompass at point P.Make the setting wideenough so that when an arc is drawn, itintersects y}34}x1}14}in two places. Labelthese points of intersection Aand B.2.Put the compass at point Aand draw an arcbelow the line.3.Using the same compass setting, put thecompass at point Band draw an arc tointersect the one drawn in step 2. Label the
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This note was uploaded on 12/19/2011 for the course MAC 1140 taught by Professor Dr.zhan during the Fall '10 term at UNF.