Pre-Calculus Homework Solutions 76

# Pre-Calculus Homework Solutions 76 - 27 2x 3y 3y y 32b 9 2x...

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27. 2 x 2 3 y 5 ¬ 2 9 2 3 y 5 ¬ 2 2 x 2 9 y 5 ¬ } 2 3 } x 1 3 The perpendicular segment from the point (2, 0) to the line y 5 } 2 3 } x 1 3 appears to intersect the line y 5 } 2 3 } x 1 3 at (0, 3). Use the Distance Formula to find the distance between (2, 0) and y 5 } 2 3 } x 1 3. d 5 ¬ Ï ( x 2 2 w x 1 ) 2 1 w ( y 2 2 w y 1 ) 2 w 5 ¬ Ï (2 2 0 w ) 2 1 (0 w 2 3) 2 w 5 ¬ Ï 2 2 1 ( w 2 3) 2 w 5 ¬ Ï 13 w The distance between the line y 5 } 2 3 } x 1 3 and the point (2, 0) is Ï 13 w units. 28. Given: , is equidistant to m. n is equidistant to m. Prove: , i n Paragraph proof: We are given that , is equidistant to m , and n is equidistant to m .By definition of equidistant, , is parallel to m , and n is parallel to m .By definition of parallel lines, slope of , 5 slope of m ,and slope of n 5 slope of m .By substitution, slope of , 5 slope of n . Then, by definition of parallel lines, , i n. 29. It is everywhere equidistant from the ceiling. 30. The plumb line will be vertical and will be perpendicular to the floor. The shortest distance from a point to the floor will be along the plumb line. 31. a 5 3, b 5 4, c 5 6, ( x 1 , y 1 ) 5 (4, 6) 5 ¬ 5 ¬ 5 ¬ } 3 5 0 } or 6 32a. 32b.
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## This note was uploaded on 12/19/2011 for the course MAC 1140 taught by Professor Dr.zhan during the Fall '10 term at UNF.

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