Pre-Calculus Homework Solutions 99

Pre-Calculus Homework Solutions 99 - Page 210 Check for...

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Page 210 Check for Understanding 1. Two triangles can have corresponding congruent angles without corresponding congruent sides. / A > / D , / B > / E , and / C > / F .However, A w B w > ± D w E w ,so n ABC > ± n DEF . 2. Sample answer: In n ABC , A w B w is the included side of / A and / B . 3. AAS can be proven using the Third Angle Theorem. Postulates are accepted as true without proof. 4. Given: G w H w i K w J w , G w K w i H w J w Prove: n GJK > n JGH Proof: 5. Given: X w W w i Y w Z w , / X > / Z Prove: n WXY > n YZW Proof: 6. Given: Q w S w bisects / RST ; / R > / T . Prove: n QRS > n QTS Proof: We are given that / R > / T and Q w S w bisects / RST , so by definition of angle bisector, / RSQ > / TSQ .By the Reflexive Property, Q w S w > Q w S w . n QRS > n QTS by AAS. 7. Given: / E > / K , / DGH > / DHG , E w G w > K w H w Prove: n EGD > n KHD Proof: Since / EGD and / DGH are linear pairs, the angles are supplementary. Likewise, / KHD and / DHG are supplementary. We are given that / DGH > / DHG .Angles supplementary to congruent angles are congruent so / EGD > / KHD .Since we are given that / E > / K and E w G w > K w H w , n EGD > n KHD by ASA. 8. This cannot be determined. The information given cannot be used with any of the triangle congruence postulates, theorems or the definition of congruent
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This note was uploaded on 12/19/2011 for the course MAC 1140 taught by Professor Dr.zhan during the Fall '10 term at UNF.

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