This preview shows page 1. Sign up to view the full content.
Page 210
Check for Understanding
1.
Two triangles can have corresponding congruent
angles without corresponding congruent sides.
/
A
>
/
D
,
/
B
>
/
E
, and
/
C
>
/
F
.However,
A
w
B
w
>
±
D
w
E
w
,so
n
ABC
>
±
n
DEF
.
2.
Sample answer: In
n
ABC
,
A
w
B
w
is the included side
of
/
A
and
/
B
.
3.
AAS can be proven using the Third Angle Theorem.
Postulates are accepted as true without proof.
4. Given:
G
w
H
w
i
K
w
J
w
,
G
w
K
w
i
H
w
J
w
Prove:
n
GJK
>
n
JGH
Proof:
5. Given:
X
w
W
w
i
Y
w
Z
w
,
/
X
>
/
Z
Prove:
n
WXY
>
n
YZW
Proof:
6. Given:
Q
w
S
w
bisects
/
RST
;
/
R
>
/
T
.
Prove:
n
QRS
>
n
QTS
Proof:
We are given that
/
R
>
/
T
and
Q
w
S
w
bisects
/
RST
, so by definition of angle bisector,
/
RSQ
>
/
TSQ
.By the Reflexive Property,
Q
w
S
w
>
Q
w
S
w
.
n
QRS
>
n
QTS
by AAS.
7. Given:
/
E
>
/
K
,
/
DGH
>
/
DHG
,
E
w
G
w
>
K
w
H
w
Prove:
n
EGD
>
n
KHD
Proof:
Since
/
EGD
and
/
DGH
are linear pairs,
the angles are supplementary. Likewise,
/
KHD
and
/
DHG
are supplementary. We are given that
/
DGH
>
/
DHG
.Angles supplementary to
congruent angles are congruent so
/
EGD
>
/
KHD
.Since we are given that
/
E
>
/
K
and
E
w
G
w
>
K
w
H
w
,
n
EGD
>
n
KHD
by ASA.
8.
This cannot be determined. The information given
cannot be used with any of the triangle congruence
postulates, theorems or the definition of congruent
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 12/19/2011 for the course MAC 1140 taught by Professor Dr.zhan during the Fall '10 term at UNF.
 Fall '10
 Dr.Zhan
 Calculus, PreCalculus, Angles

Click to edit the document details