17. Given:/F>/J,/E >/HEwCw>GwHwProve:EwFw>HwJwProof:We are given that /F>/J,/E >/H,and EwCw>GwHw.By the Reflexive Property,CwGw>CwGw.Segment addition results in EG5EC1CGand CH5CG1GH.By the definitionof congruence,EC5GHand CG5CG.Substituteto find EG5CH.By AAS,nEFG >nHJC.ByCPCTC,EwFw>HwJw.18. Given:TwXwiSwYw/TXY>/TSYProve:nTSY >nYXTProof:Since TwXwiSwYw,/YTX >/TYSbyAlternate Interior Angles Theorem.TwYw>TwYwbythe Reflexive Property. Given /TXY >/TSY,nTSY >nYXTby AAS.19. Given:/MYT >/NYT/MTY >/NTYProve:nRYM >nRYNProof:20. Given:nBMI>nKMTIwPw>PwTwProve:nIPK>nTPBProof:21. Explore:We are given the measurement of oneside of each triangle. We need to determinewhether two triangles are congruent.Plan:CwDw>GwHw, because the segments have thesame measure./CFD >/HFGbecause verticalangles are congruent. Since Fis the midpoint ofDwGw,DwFw>FwGw.
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This note was uploaded on 12/19/2011 for the course MAC 1140 taught by Professor Dr.zhan during the Fall '10 term at UNF.