Pre-Calculus Homework Solutions 101

Pre-Calculus Homework Solutions 101 - 17. Given: F E EC...

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17. Given: / F > / J , / E > / H E w C w > G w H w Prove: E w F w > H w J w Proof: We are given that / F > / J , / E > / H , and E w C w > G w H w .By the Reflexive Property, C w G w > C w G w .Segment addition results in EG 5 EC 1 CG and CH 5 CG 1 GH .By the definition of congruence, EC 5 GH and CG 5 CG .Substitute to find EG 5 CH .By AAS, n EFG > n HJC .By CPCTC, E w F w > H w J w . 18. Given: T w X w i S w Y w / TXY > / TSY Prove: n TSY > n YXT Proof: Since T w X w i S w Y w , / YTX > / TYS by Alternate Interior Angles Theorem. T w Y w > T w Y w by the Reflexive Property. Given / TXY > / TSY , n TSY > n YXT by AAS. 19. Given: / MYT > / NYT / MTY > / NTY Prove: n RYM > n RYN Proof: 20. Given: n BMI > n KMT I w P w > P w T w Prove: n IPK > n TPB Proof: 21. Explore: We are given the measurement of one side of each triangle. We need to determine whether two triangles are congruent. Plan: C w D w > G w H w , because the segments have the same measure. / CFD > / HFG because vertical angles are congruent. Since F is the midpoint of D w G w , D w F w > F w G w .
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This note was uploaded on 12/19/2011 for the course MAC 1140 taught by Professor Dr.zhan during the Fall '10 term at UNF.

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