Pre-Calculus Homework Solutions 108

Pre-Calculus Homework Solutions 108 - 42. A; m ZXY m PYZ...

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Unformatted text preview: 42. A; m ZXY m PYZ ¬90 m ZXY 26 ¬90 m ZXY ¬64 PYZ is isosceles since YP YZ, so m YPZ m YZP. m YPZ m YZP m PYZ ¬180 2(m YPZ) 26 ¬180 2(m YPZ) ¬154 m YPZ ¬77 m XPZ m YPZ ¬180 m XPZ 77 ¬180 m XPZ ¬103 m XZP m XPZ m PXZ ¬180 m XZP 103 64 ¬180 m XZP ¬13 ¬ (5 1)2 [1 ( 5)]2 ¬ 16 36 or 52 EG ¬ [ 1 ( 4)]2 [2 ( 3)]2 ¬ 9 25 or 34 RS ¬ (4 5)2 (0 1)2 ¬ 1 1 or 2 GH ¬ [2 ( 1)]2 (1 2)2 ¬ 9 1 or 10 QS ¬ (4 1)2 [0 ( 5)]2 ¬ 9 25 or 34 EH ¬ [2 ( 4)]2 [1 ( 3)]2 ¬ 36 16 or 52 The corresponding sides are not congruent so QRS is not congruent to EGH. 47. QR 48. x2 y1 2 Page 221 , y2 2 3 95 N D, G I, AN SD Prove: ANG SDI G 49. S F T F F F D q T F F F T F F T T F T T F T F I p T A F T T T p q p or q R V 50. S U m k and T F F F T T F T F F F 51. m T T k T Proof: We are given that VR RS, UT SU and RS US. Perpendicular lines form four right angles so R and U are right angles. R U because all right angles are congruent. RSV UST since vertical angles are congruent. Therefore, VRS TUS by ASA. F T F z T F F F F F T T T F F T m T T ¬ [1 ( 3)]2 (2 1)2 ¬ 16 1 or 17 EG ¬ (2 6)2 [ 3 ( 2)]2 ¬ 16 1 or 17 RS ¬ ( 1 1)2 ( 2 2)2 ¬ 4 16 or 20 GH ¬ (4 2)2 [1 ( 3)]2 ¬ 4 16 or 20 QS ¬ [ 1 ( 3)]2 ( 2 1)2 ¬ 4 9 or 13 EH ¬ (4 6)2 [1 ( 2)]2 ¬ 4 9 or 13 Each pair of corresponding sides has the same measure so they are congruent. QRS EGH by SSS. y T 46. QR Chapter 4 T F N Proof: We are given N D and G I. By the Third Angle Theorem, A S. We are also given AN SD. ANG SDI by ASA. 45. Given: VR RS, UT SU, RS US Prove: VRS TUS T F Maintain Your Skills 44. Given: a and b T 2, 2 12 18 2 , 2 or (6, 9) b T 13 a F 43. D; x1 T 52. x1 53. x1 54. x1 y x2 y1 2 , y2 y or z 7 15 2 2 2 , 9 2 (4.5, 12) x2 y1 2 , y2 4 26 2, 2 ( 1, x2 y1 2 , y2 2 3 3) 7.5 2.5 4 2, 2 (5.25, 3.25) 110 ( 12) 2 ...
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This note was uploaded on 12/19/2011 for the course MAC 1140 taught by Professor Dr.zhan during the Fall '10 term at UNF.

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