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3.
B; let
x
represent the length of the shadow. Use
the Pythagorean Theorem to solve for
x
to the
nearest foot.
12
2
5
¬
9
2
1
x
2
144
5
¬
81
1
x
2
63
5
¬
x
2
8
<
¬
x
The shadow is about 8 feet long.
4.
D
5.
D; the slope of the line in Kris’s graph can be
found using points (0, 3) and (4, 11).
}
(
(
y
x
2
2
2
2
y
x
1
1
)
)
} 5
}
1
4
1
2
2
0
3
}
or 2
The slope of the line in Mitzi’s graph is the same
as the slope of the line in Kris’s graph, or 2. So
the line in Mitzi’s graph has equation
y
5
2
x
1
b
,
or 2
x
2
y
52
b
. The only answer of this form is
2
x
2
y
5
1, so
2
b
5
1 or
b
1.
6.
B;
m
/
EFG
5
¬
m
/
FDE
1
m
/
FED
9
x
1
7
5
¬
5
x
1
5
x
9
x
1
7
5
¬
10
x
7
5
¬
x
m
/
EFG
5
9(7)
1
7
5
70
7.
C;
n
ABD
>
n
CBD
, so
n
CBD
is a flip of
n
ABD
over the
x
axis. Corresponding points have the
same
x
coordinate and opposite
y
coordinates.
8.
A; if we know
B
w
C
w
>
C
w
E
w
then
n
ACB
>
n
DCE
by
SAS.
9.
3
s
2
(2
s
3
2
7)
5
6
s
5
2
21
s
2
10.
Brian’s second statement was the converse of his
original statement.
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This note was uploaded on 12/19/2011 for the course MAC 1140 taught by Professor Dr.zhan during the Fall '10 term at UNF.
 Fall '10
 Dr.Zhan
 Calculus, PreCalculus, Pythagorean Theorem, Slope

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