3.B; let xrepresent the length of the shadow. Usethe Pythagorean Theorem to solve for xto thenearest foot.1225¬921x21445¬811x2635¬x28<¬xThe shadow is about 8 feet long.4.D5.D; the slope of the line in Kris’s graph can befound using points (0, 3) and (4, 11).}((yx2222yx11))} 5}1412203}or 2The slope of the line in Mitzi’s graph is the sameas the slope of the line in Kris’s graph, or 2. Sothe line in Mitzi’s graph has equation y52x1b,or 2x2y52b. The only answer of this form is2x2y51, so2b51 or b1.6.B;m/EFG5¬m/FDE1m/FED9x175¬5x15x9x175¬10x75¬xm/EFG59(7)175707.C;nABD>nCBD, so nCBDis a flip of nABDover the x-axis. Corresponding points have thesame x-coordinate and opposite y-coordinates.8.A; if we know BwCw>CwEwthen nACB >nDCEbySAS.9.3s2(2s327)56s5221s210.Brian’s second statement was the converse of hisoriginal statement.
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This note was uploaded on 12/19/2011 for the course MAC 1140 taught by Professor Dr.zhan during the Fall '10 term at UNF.