Pre-Calculus Homework Solutions 122

# Pre-Calculus Homework Solutions 122 - 15. WP is an angle...

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15. W w P w is an angle bisector, so m / HWP 5 } 1 2 } 1 m / HWA 2 . x 1 12 5 ¬ } 1 2 } (4 x 2 16) x 1 12 5 ¬ 2 x 2 8 12 5 ¬ x 2 8 20 5 ¬ x W w P w is a median, so A w P w > P w H w . 3 y 1 11 5 ¬ 7 y 2 5 11 5 ¬ 4 y 2 5 16 5 ¬ 4 y 4 5 ¬ y m / PAW 5 ¬ 3 x 2 2 5 ¬ 3(20) 2 2 5 ¬ 58 m / PWA 5 m / HWP because W w P w is an angle bisector. So, m / PWA 5 ¬ x 1 12 5 ¬ 20 1 12 or 32 m / WPA 1 m / PAW 1 m / PWA 5 ¬ 180 m / WPA 1 58 1 32 5 ¬ 180 m / WPA 5 ¬ 90 / WPA is a right angle, so W w P w is also an altitude. 16. W w P w bisects A w H w , so A w P w > P w H w . 6 r 1 4 5 ¬ 22 1 3 r 3 r 1 4 5 ¬ 22 3 r 5 ¬ 18 r 5 ¬ 6 W w P w is perpendicular to A w H w ,so m / HPW 5 90. m / WHA 1 m / HWP 1 m / HPW 5 ¬ 180 8 q 1 17 1 10 1 q 1 90 5 ¬ 180 9 q 1 117 5 ¬ 180 9 q 5 ¬ 63 q 5 ¬ 7 m / HWP 5 ¬ 10 1 q 5 ¬ 10 1 7 5 ¬ 17 17. Always; each median is always completely contained in the interior of the triangle, so the intersection point must also be inside the triangle. 18.
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## This note was uploaded on 12/19/2011 for the course MAC 1140 taught by Professor Dr.zhan during the Fall '10 term at UNF.

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