Pre-Calculus Homework Solutions 147

# Pre-Calculus Homework Solutions 147 - But this says that...

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149 Chapter 5 26. Using the SSS Inequality, 54 . 28 so 41 . x 1 20 or 21 . x . x 1 20 . 0, so x .2 20. The two inequalities can be written as the compound inequality 2 20 , x , 21. 27. In the upper triangle, the bottom angle has measure 90 2 60 or 30, so the upper left angle has measure 180 2 (95 1 30) or 55. Then by the SAS Inequality, 5 x 1 3 . 3 x 1 17. 5 x 1 3 ¬ . 3 x 1 17 2 x 1 3 ¬ . 17 2 x ¬ . 14 x ¬ . 7 Chapter 5 Practice Test Page 277 1. b 2. c 3. a 4. HP 5 PJ 5 x 2 16 5 ¬ 3 x 1 8 2 x 2 16 5 ¬ 8 2 x 5 ¬ 24 x 5 ¬ 12 HJ 5 ¬ HP 1 PJ 5 ¬ 5(12) 2 16 1 3(12) 1 8 5 ¬ 88 5. m / GJN 5 ¬ m / NJH 6 y 2 3 5 ¬ 4 y 1 23 2 y 2 3 5 ¬ 23 2 y 5 ¬ 26 y 5 ¬ 13 m / GJH 5 ¬ m / GJN 1 m / NJH 5 ¬ 6(13) 2 3 1 4(13) 1 23 5 ¬ 150 6. m / HMG 5 ¬ 90 4 z 1 14 5 ¬ 90 4 z 5 ¬ 76 z 5 ¬ 19 7. By the Exterior Angle Theorem, m / 8 . m / 7 and m / 5 . m / 8. By transitivity, m / 5 . m / 7, so / 5 has the greatest measure. 8. By the Exterior Angle Theorem, m / 8 . m / 7 and m / 8 . m / 6, so / 8 has the greatest measure. 9. By the Exterior Angle Theorem, m / 1 . m / 6 and m / 1 . m / 9, so / 1 has the greatest measure.
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