Pre-Calculus Homework Solutions 192

Pre-Calculus Homework Solutions 192 - 55. The smallest...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
55. The smallest angle is opposite the side with the smallest measure, 20. Let x and 20 2 x be the measures of the segments formed by the angle bisector. By the Angle Bisector Theorem, } 20 x 2 x } 5 ¬ } 2 3 4 0 } . } 20 x 2 x } 5 ¬ } 2 3 4 0 } 30 x 5 ¬ 480 2 24 x 54 x 5 ¬ 480 x 5 ¬ } 8 9 0 } or 8 } 8 9 } 20 2 x 5 ¬ } 10 9 0 } or 11 } 1 9 } The segments have measures 8 } 8 9 } and 11 } 1 9 } . 56. By the Exterior Angle Inequality Theorem, m / 8 . m / 6, m / 8 . m / 3 1 m / 4, and m / 8 . m / 2. Thus, the measures of / 6, / 4, / 2, and / 3 are all less than m / 8. 57. By the Exterior Angle Inequality Theorem, m / 1 , m / 5 and m / 1 , m / 7. Thus, the measures of / 5 and / 7 are greater than m / 1. 58. By the Exterior Angle Inequality Theorem, m / 1 , m / 7 and m / 6 , m / 7. Thus, the measures of / 1 and / 6 are less than m / 7. 59. By the Exterior Angle Inequality Theorem, m / 2 . m / 6, m / 7 . m / 6, and m / 8 . m / 6. Thus, the measures of / 2, / 7, and / 8 are all greater than m / 6. 60. y 5 mx 1 b y 5 2 x 1 4 61. m 5 } 2 0 8 2 2 2 0 } 5 } 2 2 8 2 } or 4 y 5 mx 1 b y 5 4 x 1 ( 2 8) y 5 4 x 2 8 62. m 5 } 2 0 1 2 2 6 2 } 5 } 2 2 6 3 } or 2 y 2 y 1 5 ¬ m ( x 2 x 1 ) y 2 6 5 ¬ 2( x 2 2) y 2 6 5 ¬ 2 x 2 4
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/19/2011 for the course MAC 1140 taught by Professor Dr.zhan during the Fall '10 term at UNF.

Ask a homework question - tutors are online