Pre-Calculus Homework Solutions 213

Pre-Calculus Homework Solutions 213 - 5 } 4 x 8 1 } x 1 5...

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18. K w E w and F w G w are parallel, so KF 5 EG .Since SG is 123 feet and EG is 6 feet, SE is 117 feet. tan37° 5 ¬ } 1 K 1 E 7 } KE tan37° 5 ¬ 117 KE 5 ¬ } ta 1 n 1 3 7 } ¬ KE < ¬ 155.3 ¬ KE 5 FG , so the distance between kirk and the geyser is about 155.3 feet. 19. tan60° 5 ¬ } D AC C } AC tan60° 5 ¬ DC tan30° 5 ¬ } D BC C } tan30° 5 ¬ } AC t B a C n60° } BC tan30° 5 ¬ AC tan60° BC 5 ¬ } AC ta t n a 3 n 0 6 ° } AC 1 200 5 ¬ AC 1 } t t a a n n 6 3 0 0 ° ° } 2 AC 1 200 5 ¬ AC (3) 200 5 ¬ 3 AC 2 AC 200 5 ¬ 2 AC 100 5 ¬ AC BC 5 ¬ AC 1 200 5 ¬ 100 1 200 or 300 The observers are 100 feet and 300 feet from the base of the tree. 20. Let x represent the distance from the spotlight to the base of the cloud formation. tan62.7° 5 ¬ } 8 x 3 } 83tan62.7° 5 ¬ x 160.8 < ¬ x The ceiling is about 160.8 1 1.5 or 162.3 meters. 21. RF 5 48 and m / RFP 5 10. Find RP . sin10° 5 ¬ } R R P F } sin10° 5 ¬ } R 48 P } 48sin10° 5 ¬ RP ¬ 8.3 < ¬ RP ¬ The raised end of the treadmill is about 8.3 inches off the floor. 22. RP 5 10 and RF 5 48. Let x 5 m / RFP . sin x ° 5 ¬ } R R P F } sin x ° 5 ¬ } 1 4 0 8 } x 5 ¬ sin 2 1 1 } 1 4 0 8 } 2 ¬ x < ¬ 12 ¬ The incline of the treadmill is about 12°. 23. Let x i represent the rise at each stage i , i 5 1, 2, 3, 4, 5. The length of the treadmill is 48 inches. Suppose the incline at the beginning of the exam is 10°. Stage 1: sin10°
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Unformatted text preview: 5 } 4 x 8 1 } x 1 5 48sin10 x 1 < 8.3351 Stage 2: sin12 5 } 4 x 8 2 } x 2 5 48sin12 x 2 < 9.9798 Stage 3: sin14 5 } 4 x 8 3 } x 3 5 48sin14 x 3 < 11.6123 Stage 4: sin16 5 } 4 x 8 4 } x 4 5 48sin16 x 4 < 13.2306 Stage 5: sin18 5 } 4 x 8 5 } x 5 5 48sin18 x 5 5 14.8328 x 2 2 x 1 < 9.9798 2 8.3351 < 1.6447 x 3 2 x 2 < 11.6123 2 9.9798 < 1.6325 x 4 2 x 3 < 13.2306 2 11.6123 < 1.6183 x 5 2 x 4 < 14.8328 2 13.2306 < 1.6026 No, the end of the treadmill does not rise the same distance each time. The changes in the rise of the treadmill between stages are only approximately the same, about 1.6 inches. 24. tan25.6 5 } D BC C } BC tan25.6 5 DC tan15.85 5 } D AC C } C D 25.6 15.85 0.5 km B A P R F P R F C D 60 30 200 ft B A F G E S K 6 ft 37 123 ft 215 Chapter 7...
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This note was uploaded on 12/19/2011 for the course MAC 1140 taught by Professor Dr.zhan during the Fall '10 term at UNF.

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