Pre-Calculus Homework Solutions 221

# Pre-Calculus Homework Solutions 221 - 2 53 c tan26.5° a2...

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Unformatted text preview: 2 53. c tan26.5° a2 b2 2ab ¬ 10 2 54. c a2 b2 2ab ¬6 2 55. c 45. Let y represent the amount of the window that will get direct sunlight. 72 82 2(7)(8) 49 ¬ 100 112 64 13 13 ¬ 112 ¬ 112 a2 b2 2ab 5 ¬ 10 2(5)(8) 8 y ¬ 7 07 2. 2.07tan26.5° ¬7 y y ¬7 2.07tan26.5° 2 42 92 2(4)(9) 6 ¬ 36 172 81 ¬ 61 ¬ 61 72 72 y ¬5.97 About 5.97 feet of the window will get direct sunlight. sin J j k 8 17 sin J 0.47 46. sin J sin L sin L k 15 17 sin L 0.88 sin J j k 20 29 sin J 0.69 47. sin J sin L sin L k 21 29 sin L 0.72 sin J j k 12 24 1 2 sin J 0.50 48. sin J sin J sin L sin L k 12 3 24 3 2 sin L 0.87 sin L sin J j k 72 14 2 2 sin J 0.71 49. sin J sin J sin L sin L sin L k 72 14 2 2 cos J cos J k 15 17 cos J 0.88 cos L j k 8 17 cos L 0.47 cos L cos J cos J k 21 29 cos J 0.72 cos L j k 20 29 cos L 0.69 cos L cos J cos J k 12 3 24 3 2 cos J 0.87 cos J tan J tan J tan J 0.53 tan L tan L j 15 8 tan L tan J tan L tan L 2 32 102 2(3)(10) ¬ 81 960 100 7 ¬ 28 ¬ 15 60 a2 b2 2ab 5 ¬ 11 2(5)(7) 7 2 ¬ 121 tan J tan J k tan J 2 25 70 49 ¬ 47 70 Page 383 Practice Quiz 2 0.58 cos J 2 j 12 12 3 3 3 tan L cos J ¬9 1.05 0.50 cos J a2 b2 2ab 2 58. c j 21 20 tan L 2 ¬ 11 80 256 16 128 103 ¬ 128 ¬ 103 128 0.95 tan J 2 2 57. c tan J tan J 64 16 ¬ 13 2(16)(4) 4 20 21 tan L 25 80 2 a2 b2 2ab 2 ¬ 169 j tan J cos L 72 14 2 2 2 1.88 cos L cos L 2 56. c 2 ¬ 100 8 15 j k 12 24 1 2 cos L j 2 ¬ 16 10 1. tan x° 1 j 12 3 12 tan L 3 2. ¬tan x tan L x ¬58.0 ¬ 9x .7 cos17° 9.7cos17° 9.3 ¬x ¬x j cos53° ¬ 32 x x cos53° 3. 1.73 16 10 ¬32 x 32 ¬ cos 53° x ¬53.2 0.71 cos J cos L cos L cos L j k 72 14 2 2 tan J 72 72 tan J 1.00 tan L tan L tan L 4. j 72 72 5m 15 15 1.00 sin L 50. m 1 0.71 cos L 0.71 54 120 Exterior Angle Theorem m 1 66 51. m 2 54 alternate interior 52. m 2 m 3 36 ¬180 Angle Sum Theorem 54 m 3 36 ¬180 m 3 90 ¬180 m 3 ¬90 500 m x tan15° x ¬ 500x 5 495tan15° ¬x 132.6 ¬x The distance is about 132.6 meters. 223 Chapter 7 ...
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