Pre-Calculus Homework Solutions 235

# Pre-Calculus Homework Solutions 235 - S w X w is...

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6. D; the height of the original tower is AB 1 BC . sin36° ¬ 5 } B 60 C } BC sin36° ¬ 5 60 BC ¬ 5 } sin 6 3 0 } BC ¬ < 102 AB 1 BC ¬ 5 60 1 102 or 162 feet. 7. C; } sin r R } ¬ 5 } sin s S } } sin 1 3 4 } ¬ 5 } si 2 n 1 S } 21sin34° ¬ 5 14sin S } 21s 1 in 4 34° } ¬ 5 sin S sin 2 1 1 } 21s 1 in 4 34° } 2 ¬ 5 S 57° ¬ < S 8. m / C 1 m / BDC 1 m / DBC ¬ 5 180 90 1 m / BDC 1 55 ¬ 5 180 m / BDC ¬ 5 35 m / ADB 1 m / BDC ¬ 5 m / ADC m / ADB 1 35 ¬ 5 61 m / ADB ¬ 5 26 m / A 1 m / ABD 1 m / ADB 5 180 69 1 m / ABD 1 26 5 180 m / ABD 5 85 m / ABC 5 m / ABD 1 m / DBC 5 85 1 55 5 140 9. m 5 } x y 2 2 2 2 y x 1 1 } 5 } 5 1 0 0 2 2 3 0 2 } 5 } 1 1 8 0 } or } 9 5 } 10. y 2 y 1 ¬ 5 m ( x 2 x 1 ) y 2 32 ¬ 5 } 9 5 } ( x 2 0) y ¬ 5 } 9 5 } x 1 32 11. } U YZ V } 5 } T X V Z } 5 } 1 6 0 } or } 3 5 } 12. Let x represent Dee’s height above the water. sin41° ¬ 5 } 50 x 0 } 500sin41° ¬ 5 x 328 ¬ < x Dee is about 328 feet above the water. 13. Since Sasha is equidistant from Toby and Rani, S w T w and S w R w are congruent and n STR is an isosceles triangle. According to the Isosceles Triangle Theorem, / T and / R are also congruent.
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Unformatted text preview: S w X w is perpendicular to T w R w , so / SXT and / SXR are both right angles and congruent. Two corresponding angles and the corresponding nonincluded sides are congruent (AAS Theorem), so n STX and n SRX are congruent triangles. Since these triangles are congruent, the corresponding sides T w X w and R w X w are congruent and have equal length; therefore when Sasha is jumping at Point X she will be at the midpoint between Toby and Rani. 237 Chapter 7...
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