Pre-Calculus Homework Solutions 253

Pre-Calculus Homework Solutions 253 - 41. Given: AB DC AB...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
255 Chapter 8 For (2, 2 2) and (0, 4), R w T w i Q w S w . slope of S w R w 5 ¬ } 1 1 2 2 ( ( 2 2 1 1 ) ) } 5 ¬ 1 Suppose T is (0, 4). slope of Q w T w 5 ¬ } 0 4 2 2 ( 2 2 2) } 5 ¬ 1 So S w R w i Q w T w . So, (2, 2 2), ( 2 4, 0), and (0, 4) are the possibilities for the fourth vertex. Any of these values results in both pairs of opposite sides being parallel, and thus, the four points form a parallelogram. 37. JKLM is a parallelogram because K w M w and J w L w are diagonals that bisect each other. 38. If both pairs of opposite sides are parallel and congruent, then the watchbox is a parallelogram. 39. Given: A w D w > B w C w A w B w > D w C w Prove: ABCD is a parallelogram. Proof: 40. Given: A w E w > E w C w , D w E w > E w B w Prove: ABCD is a parallelogram. Proof: 41. Given: A w B w > D w C w A w B w i D w C w Prove: ABCD is a parallelogram. Proof: 42. This theorem is not true. ABCD is a parallelogram with diagonal B w D w , / ABD ± / CBD . 43. Given: ABCDEF is a regular hexagon. Prove: FDCA is a parallelogram.
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online