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257
Chapter 8
59.
Two angles are given, 60° and 90°, so this is a
30°60°90° triangle. The shorter leg is half the
length of the hypotenuse, and the longer leg is
Ï
3
w
times the length of the shorter leg. Therefore,
x
5
16
Ï
3
w
and
y
5
16.
60.
Determine the slopes of
A
w
B
w
and
B
w
C
w
.
slope of
A
w
B
w
5
¬
}
y
x
2
2
2
2
y
x
1
1
}
5
¬
}
3
6
2
2
5
2
}
5
¬
2 }
1
2
}
slope of
B
w
C
w
5
}
7
8
2
2
3
6
}
5
2
The product of the slopes of
A
w
B
w
and
B
w
C
w
is
2
1, so
A
w
B
w
'
B
w
C
w
.
61.
Determine the slopes of
A
w
B
w
and
B
w
C
w
.
slope of
A
w
B
w
5
¬
}
y
x
2
2
2
2
y
x
1
1
}
5
¬
}
0
7
2
2
(
2
2
1)
}
5
¬
5
slope of
B
w
C
w
5
}
1
4
2
2
7
0
}
52
}
3
2
}
The product of the slopes of
A
w
B
w
and
B
w
C
w
is not
2
1,
so
A
w
B
w
is not perpendicular to
B
w
C
w
.
62.
Determine the slopes of
A
w
B
w
and
B
w
C
w
.
slope of
A
w
B
w
5
¬
}
y
x
2
2
2
2
y
x
1
1
}
5
¬
}
7
5
2
2
4
0
}
5
¬
}
3
5
}
slope of
B
w
C
w
5
}
3
8
2
2
7
5
}
52
}
4
3
}
The product of the slopes of
A
w
B
w
and
B
w
C
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This note was uploaded on 12/19/2011 for the course MAC 1140 taught by Professor Dr.zhan during the Fall '10 term at UNF.
 Fall '10
 Dr.Zhan
 Calculus, PreCalculus, Angles, Slope

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