Working with the distance

# Working with the distance - In this example the power 10 is...

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Working with the distance- magnitude equation and the measured parallax of stars Complete the following table (use the tutorial on the distance-magnitude equation to help): Apparent Magnitude m v Absolute Magnitude M v Distance Modulus (m v ? M v ) Distance (parsecs)* Parallax (arc seconds) 12.2 6.6 5.6 132 = 1/132 = 0.0076 9.93 6.6 3.33 46.3 0.0216 7.0 10 = 1/10 = 0.10 11 1000 -2 0.025 4 0.040 6.6 3.33 *Distance (in parsecs) = 10 raised to the power of [(m ? M + 5)/5];
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Unformatted text preview: . In this example, the ? power ? 10 is raised to is [(12.2-6.6+5)/5] = 10.6 / 5 = 2.12. Solving: 10 2.12 = 132 pc. To solve for either the apparent magnitude or the absolute magnitude, given the other quantity and the distance in parsecs: m v ? M v =5 log (d) ? 5 m v =M v + 5 log (d) ? 5 M v = m v- 5 log (d) + 5 How you enter these numbers depends on your calculator. Work with the examples given above to figure this out....
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## This note was uploaded on 12/15/2011 for the course AST AST1002 taught by Professor Emilyhoward during the Fall '10 term at Broward College.

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