Unformatted text preview: . In this example, the ? power ? 10 is raised to is [(12.26.6+5)/5] = 10.6 / 5 = 2.12. Solving: 10 2.12 = 132 pc. To solve for either the apparent magnitude or the absolute magnitude, given the other quantity and the distance in parsecs: m v ? M v =5 log (d) ? 5 m v =M v + 5 log (d) ? 5 M v = m v 5 log (d) + 5 How you enter these numbers depends on your calculator. Work with the examples given above to figure this out....
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This note was uploaded on 12/15/2011 for the course AST AST1002 taught by Professor Emilyhoward during the Fall '10 term at Broward College.
 Fall '10
 EmilyHoward
 Astronomy

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