Statistics Homework Solutions 13

Statistics Homework Solutions 13 - 16 5(a The outcomes are...

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SECTION 2.1 13 Chapter 2 Section 2.1 1. P not defective 1 P defective 1 0 08 0 92 3. (a) The outcomes are the 16 different strings of 4 true-false answers. These are TTTT, TTTF, TTFT, TTFF, TFTT, TFTF, TFFT, TFFF, FTTT, FTTF, FTFT, FTFF, FFTT, FFTF, FFFT, FFFF . (b) There are 16 equally likely outcomes. The answers are all the same in two of them, TTTT and FFFF. Therefore the probability is 2 16 or 1 8. (c) There are 16 equally likely outcomes. There are four of them, TFFF, FTFF, FFTF, and FFFT, for which exactly one answer is “True.” Therefore the probability is 4 16 or 1 4. (d) There are 16 equally likely outcomes. There are five of them, TFFF, FTFF, FFTF, FFFT, and FFFF, for which at most one answer is “True.” Therefore the probability is 5
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Unformatted text preview: 16. 5. (a) The outcomes are the sequences of bolts that end with either #1 or #2. These are 1, 2, 31, 32, 41, 42, 341, 342, 431, 432 . (b) A = 1, 2 (c) B = 341, 342, 431, 432 (d) C = 2, 32, 42, 342, 432 (e) D = 1, 2, 31, 32 (f) A and E are not mutually exclusive because they both contain the outcome 1. B and E are not mutually exclusive because they both contain the events 341 and 431. C and E are mutually exclusive because they have no outcomes in common. D and E are not mutually exclusive because they have the events 1 and 31 in common. 7. (a) 0.6 (b) P personal computer or laptop computer P personal computer P laptop computer 6 3 9...
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This note was uploaded on 12/20/2011 for the course STA 3163 taught by Professor Mattgilg during the Fall '11 term at UNF.

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