Statistics Homework Solutions 71

# Statistics Homework Solutions 71 - 71 SUPPLEMENTARY...

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 71 SUPPLEMENTARY EXERCISES FOR CHAPTER 3 0 1. 32 833.  Â¡ 362 4 0 1 36 Â¡Â¥Â¨ Â¤Â¥ Â¨ Â¤ Â¡ Â¡ dS Ïƒs ds Â¡ Â¨ Â¡ 36 m2 12 894. Â¡ Â£ Â©Â¥ Â¤ Â¡ Â¤ Â¦Â¥ Â¨ Â¤ Â¡ Â¡ 142 314 0 1 14 Â¡Â¥Â¨  Â¡ Â¨ Â¡ Â£ Â¡ 14 m2 12 894 Ï€s2 8  Â¡ (b) The estimated area of a semicircle is C dC dC Ï€s 4 142 314, ÏƒC Ïƒs ds ds  Â¡ C Â¡ 32 833 Â¨ S 181 2 Ïƒ s Â¡ The estimated area is S dS 2s 362 4, ÏƒS ds s2 Â¨ 21. (a) Let s be the measured side of the square. Then s (c) This is not correct. Let s denote the length of a side of the square. Since S and C are both computed in terms of s, they are not independent. In order to compute ÏƒA correctly, we must express A directly in terms of s: dA A s2 2Ï€s2 8 s2 1 Ï€ 4 . So ÏƒA Ïƒs 2s 1 Ï€ 4 Ïƒs 65 m2 . ds Â£ Â¢ Â¤ 11 16871 Â¨ Â¡ Â¡ P1 P2 Â¥ Â¡ Â¤ Â¡ Â¨ Â¥ Â£ Â¢ Â¤ Â¡ Â£ Â¡ Â¨ Â¡ Â¨ Â¡ Â¨ Â¨ 2 Ïƒ2 2 P Â¡ Â¡ âˆ‚P3 âˆ‚P2 Â¡ Â¢ 0 10 Â¡ Â¡ Â¤ Â¡ 0 10 MPa Â¨ Â¡ Â¨ Â¡ âˆ‚2 P3 âˆ‚2 P3 32 12 32 12 0 25 P1 P2 0 042557, 0 25 P2 P1 0 011773 2 2 âˆ‚P1 âˆ‚P2 The bias corrected estimate is 1 âˆ‚2 P3 âˆ‚2 P3 P3 Ïƒ2 1 Ïƒ2 2 11 16871 0 5 0 042557 0 12 0 011773 0 22 P P 2 2 2 âˆ‚P1 âˆ‚P2 Â¨ Â¡ Â¡ Â¦ Â¦ Â¥ Â¨ Â¤ Â¡ Â¡ Â¨ Â¡ Â¡ Â¦ Â¦ Â¨ Â¤ Â¨ Â¡ Â¥ Â¨ Â¤ Â¨ Â¡ Â¥Â¨ Â¤ Â¡ Â¨ Â¡ Â¡ Â¡ Â¥ Â¨ Â¢ Â¤ Â¡ Â¡ Â¡ Â¡ Â¡ (c) No. The difference between the two estimates is much less than the uncertainty. Â¡ Â¢Â¥ Â¡ Â¡ Â¤ Ïƒ2 1 P 11 16916. Â¨ Â¡ Â¨ Â¡ 2 Â¨ Â¢ (b) 11 16871 0 2, P Â¡ P3 âˆ‚P3 âˆ‚P1 ÏƒP3 23. (a) P1 8 1 ÏƒP1 0 1, P2 15 4 ÏƒP2 âˆ‚P3 P2 0 689426 âˆ‚P1 2 P1 P2 âˆ‚P3 P1 0 36262 âˆ‚P2 2 P1 P2 ...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online