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Statistics Homework Solutions 107

Statistics Homework Solutions 107 - 107 SECTION 4.12 It...

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SECTION 4.12 107 It follows that X is approximately normal with mean μ X 500 0 7 350 and variance σ 2 X 500 0 7 0 3 105, and Y is approximately normal with mean μ Y 500 0 8 400 and variance σ 2 X 500 0 8 0 2 80. Let T X Y be the total number of rivets that meet the specification. Then T is approximately normal with mean μ T μ X μ Y 350 400 750, and standard deviation σ T σ 2 X σ 2 Y 105 80 13 601471. To find P T 775 , use the continuity correction and find the z -score of 775.5. The z -score of 775.5 is 775 5 750 13 601471 1 87.
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