Statistics Homework Solutions 121

Statistics Homework Solutions 121 - 121 SECTION 5.3 (c) Let...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 121 SECTION 5.3 (c) Let n be the required sample size. ¡ ¤ ¡ ¡ ¡ ¨ ¨ ¡ ¨ ¨ ¨ ¨ ¡ ¨ (e) 90% ¤¨ (d) 80% ¡ (c) 99% ¤ ©¥ ¨ £ (b) 98% ¢ 3. (a) 95% ¥ (d) 2.048 4 . Solving for n yields n ¡ ¨ ¨ ¨ ¢ (c) 63.657 ¤ ¨ ¤ ¥ £ (b) 2.447 n ¡ ¤ 1. (a) 1.796 05 ¤ ¢ Section 5.3 1 645 0 5 1 ¡ ¡ ¡¥ Since there is no preliminary estimate of p available, replace p with 0 5. ˜ ˜ p ˜ ¤ ¥ £ p1 ˜ n n 748. 4. ¢ 1 645 p ˜ 4. ¥ ¡ p1 ˜ 658. (c) Let n be the required sample size. Then n satisfies the equation 0 05 The equation becomes 0 03 4 , or (0.271, 0.382). 1 645 (b) Let n be the required sample size. Then n satisfies the equation 0 03 Replacing p with 0 32642 and solving for n yields n ˜ 189 ¤ ¥ £ 0 32642 ¢ ¨ 1 645 0 32642 1 1 645. ¥ 0 32642, z 05 ¨ The confidence interval is 0 32642 4 ¡ 189 ¨ ¨ 2 ¤ ¥ £ ¡ 61 ¢ ¨ 189, p ˜ 253. ¥ ¤ 61, n 4. ¡ ¡ Replacing p with 0 21154 and solving for n yields n ˜ 15. (a) X n ¨ p ˜ ¤ ¥ £ p1 ˜ ¢ 1 96 ¥ Then n satisfies the equation 0 05 ...
View Full Document

This note was uploaded on 12/20/2011 for the course STA 3163 taught by Professor Mattgilg during the Fall '11 term at UNF.

Ask a homework question - tutors are online