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Statistics Homework Solutions 130

Statistics Homework Solutions 130 - 130 CHAPTER 5(b Let n...

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130 CHAPTER 5 (b) Let n be the required sample size. Then n satisfies the equation 0 03 1 96 ˜ p 1 ˜ p n 4 . Replacing ˜ p with 0 16484 and solving for n yields n 584. 9. The higher the level, the wider the confidence interval. Therefore the narrowest interval, (4.20, 5.83), is the 90% confidence interval, the widest interval, (3.57, 6.46), is the 99% confidence interval, and (4.01, 6.02) is the 95% confidence interval. 11. X 7 909091, s X 0 359039, n X 11, Y 8 00000, s Y 0 154919, n Y 6. The number of degrees of freedom is ν 0 359039 2 11 0 154919 2 6 2 0 359039 2 11 2 11 1 0 154919 2 6 2 6 1 14, rounded down to the nearest integer. t 14 01 2 624, so the confidence interval is 7 909091 8 00000 2 624 0 359039 2 11 0 154919 2 6 , or 0 420 0 238 . 13. Let n be the required sample size. The 90% confidence interval based on 144 observations has width
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