Statistics Homework Solutions 133

Statistics Homework Solutions 133 - 133 SECTION 6.1 Chapter...

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Unformatted text preview: 133 SECTION 6.1 Chapter 6 Section 6.1 73. The null and alternate hypotheses are H0 : µ ¡¥ ¤£ ¤ ¥ £ ¨ ¡ ¤ ¡ ¡ ¡ 750. µ0 , the P-value is the 0 0094. ¨ Thus P 2 35. Since the alternate hypothesis is of the form µ ¨ ¡ z 783 750 120 73 area to the right of z 2 35. 750 versus H1 : µ ¡ ¡ 120, n ¨ 783, s ¡ 1. (a) X ¡ (b) The P-value is 0.0094, so if H0 is true then the sample is in the most extreme 0.94% of its distribution. 160. The null and alternate hypotheses are H0 : µ ¡ 21 20, n ¡ ¨ 1 90, s 0 versus H1 : µ ¡ 3. (a) X 0. ¡ ¨ ¡ ¨ ¡ ¡ ¨ ¨ ¤ ©¥ £ ¨ ¡ ¤ ¡ ¡ 0 2584. ¨ ¡ 0 1292 µ0 , the P-value is the ¨ ¤£ ¡¥ ¨ ¢ 0 1292 ¨ Thus P ¡ 1 90 0 21 20 160 1 13. Since the alternate hypothesis is of the form µ z sum of the areas to the right of z 1 13 and to the left of z 1 13. ¡ (b) The P-value is 0.2584, so if H0 is true then the sample is in the most extreme 25.84% of its distribution. 3 15. Since the alternate hypothesis is of the form µ ¨ ¡¥ ¤£ ¨ ¨ ¡ ¨ ¡ ¤ ¥ £ ¡ ¨ ¡ ¤ ¡ 50. µ0 , the P-value is area 0 0008. ¨ ¡ Thus P 4 0 110 3 15. 50 versus H1 : µ ¡ ¨ z 51 2 50 to the right of z 110. The null and alternate hypotheses are H0 : µ ¡ 4 0, n ¨ 51 2, s ¡ 5. (a) X (b) If the mean tensile strength were 50 psi, the probability of observing a sample mean as large as the value of 51.2 that was actually observed would be only 0.0008. Therefore we are convinced that the mean tensile strength is not 50 psi or less, but is instead greater than 50 psi. ¡ ¡¥ 740 versus H1 : µ 8 07. Since the alternate hypothesis is of the form µ 740. µ0 , the P-value is the ¨ ¤£ ¡ ¡ ¤ ©¥ £ ¤ ¡ ¡ ¡ Thus P 60 8 07. ¨ ¡ z 715 740 24 area to the left of z 60. The null and alternate hypotheses are H0 : µ ¡ ¡ 24, n § 715, s ¡ 7. (a) X 0. (b) If the mean daily output were 740 tons or more, the probability of observing a sample mean as small as the value of 715 that was actually observed would be nearly 0. Therefore we are convinced that the mean daily output is not 740 tons or more, but is instead less than 740 tons. ...
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This note was uploaded on 12/20/2011 for the course STA 3163 taught by Professor Mattgilg during the Fall '11 term at UNF.

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