Statistics Homework Solutions 149

Statistics Homework Solutions 149 - H : μ 14 versus H 1 :...

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SECTION 6.9 149 Section 6.9 1. (a) The signed ranks are Signed x x 14 Rank 20 6 1 21 7 2 5 9 3 24 10 4 25 11 5 32 18 6 43 29 7 The null and alternate hypotheses are H 0 : μ 14 versus H 1 : μ 14. The sum of the positive signed ranks is S 25. n 7. Since the alternate hypothesis is of the form μ μ 0 , the P -value is the area under the signed rank probability mass function corresponding to S 25. From the signed-rank table, P 0 0391. We can conclude that the mean concentration is greater than 14 g/L. (b) The signed ranks are Signed x x 30 Rank 32 2 1 25 5 2 24 6 3 21 9 4 20 10 5 43 13 6 5 25 7 The null and alternate hypotheses are
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Unformatted text preview: H : μ 14 versus H 1 : μ 30. The sum of the positive signed ranks is S 7. n 7. Since the alternate hypothesis is of the form μ μ , the P-value is the area under the signed rank probability mass function corresponding to S 7. From the signed-rank table, P 1094. We cannot conclude that the mean concentration is less than 30 g/L. (c) The signed ranks are Signed x x 18 Rank 20 2 1 21 3 2 24 6 3 25 7 4 5 13 5 32 14 6 43 25 7...
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This note was uploaded on 12/20/2011 for the course STA 3163 taught by Professor Mattgilg during the Fall '11 term at UNF.

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