Statistics Homework Solutions 151

Statistics Homework - 151 SECTION 6.9 Signed Rank 1 2 3 4 5 6 7 8 9 10 11 12 5 12 5 14 15 16 17 18 19 20 21 22 23 24 ¨ ¨ ¨ ¨ ¨ ¨ ¨

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Unformatted text preview: 151 SECTION 6.9 Signed Rank 1 2 3 4 5 6 7 8 9 10 11 12 5 12 5 14 15 16 17 18 19 20 21 22 23 24 ¨ ¡ ¨ ¡ ¡ ¨ ¨ ¡ ¨ ¡ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¡ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¡ ¨ ¡ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¡ ¢ 24. 30. 20, compute the z-score of S and use the z table. 2 84. £ ¥ ¢ ¢ ¤ ¡ ¤¥ ¢ ¢ ¤ ¡ Since the alternate hypothesis is of the form µ table, P 0 0023. ¡ 1 24 µ0 , the P-value is the area to the right of z ¨ ¡ We can conclude that the mean conversion is greater than 30. ¡ £ ¥ 1 2n 2 84. From the z ¨ 14 ¡ nn nn ¨ ¡ S ¢ z ¨ ¨ ¨ Since n 249 5. n ¡ ¨ ¨ The sum of the positive signed ranks is S 30 versus H1 : µ ¨ ¨ The null and alternate hypotheses are H0 : µ ¡ 30 01 03 12 32 34 36 46 62 73 81 10 0 11 0 11 0 11 1 15 7 20 9 22 3 29 4 33 0 37 8 42 3 48 6 50 8 51 2 ¡ x ¡ x 30 1 30 3 28 8 26 8 33 4 33 6 34 6 36 2 37 3 38 1 40 0 19 0 41 0 41 1 14 3 91 52 3 59 4 63 0 67 8 72 3 78 6 80 8 81 2 ¡ (b) The signed ranks are ...
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This note was uploaded on 12/20/2011 for the course STA 3163 taught by Professor Mattgilg during the Fall '11 term at UNF.

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