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Statistics Homework Solutions 152

# Statistics Homework Solutions 152 - 152 CHAPTER 6 Signed...

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Unformatted text preview: 152 CHAPTER 6 Signed Rank 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 5 19 5 21 22 23 24 Â¡ Â¡ Â¡ Â¡ Â¡ Â¡ Â¡ Â¡ Â¡ Â¡ Â¡ Â¨ Â¡ Â¨ Â¡ Â¡ Â¡ Â¡ 55 27 44 80 12 8 13 9 14 0 15 0 16 9 17 3 17 7 18 8 20 4 21 4 21 6 23 6 24 7 24 9 25 8 26 2 26 2 28 2 36 0 40 7 45 9 Â¨ x Â¡ x 52 3 59 4 63 0 67 8 41 1 41 0 40 0 38 1 72 3 37 3 36 2 34 6 33 6 33 4 78 6 30 3 30 1 80 8 28 8 81 2 26 8 19 0 14 3 91 Â¡ (c) The signed ranks are Â¨ Â¡ Â¨ Â¨ Â¨ Â¨ Â¨ Â¨ Â¨ Â¨ Â¡ Â¨ Â¨ Â¡ Â¨ Â¨ Â¡ Â¨ Â¨ Â¡ Â¨ Â¨ Â¨ Â¨ Â¡ Â¨ Â¨ Â¡ Â¨ Â¨ Â¡ Â¨ Â¨ Â¡ Â¨ Â¨ Â¡ Â¨ Â¨ Â¨ Â¨ Â¡ Â¨ Â¨ Â¡ Â¨ Â¨ Â¨ Â¨ Â¡ Â¨ Â¨ Â¨ Â¨ Â¡ Â¨ Â¨ Â¡ Â¨ Â¨ Â¨ Â¡ Â¨ Â¡ Â¨ Â¢ Â¡ 55. 24. 20, compute the z-score of S and use the z table. 14 Â£ Â¥ 1 24 Â¡ Â£ Â¥ Â¢ 2 27. Â¢ Â¤Â¥ Â¡ Â¢ Â¢ Â¤ Â¡ Â¨ 0 0116 Â¡ Â¨ Â¢ 0 0116 0 0232. Â¨ Â¡ Â¡ Â¨ Â¡ From the z table, P Âµ0 , the P-value is the sum of the areas to the right of z We can conclude that the mean conversion differs from 55. Â¡ Â¡ Since the alternate hypothesis is of the form Âµ 2 27. and to the left of z 2 27 Â¨ Â¤ 1 2n Â¡ nn nn Â¨ Â¡ S Â¢ z 70 5. n Â¡ Since n Â¡ The sum of the positive signed ranks is S 55 versus H1 : Âµ Â¡ The null and alternate hypotheses are H0 : Âµ ...
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