Statistics Homework Solutions 154

Statistics Homework Solutions 154 - 154 9. CHAPTER 6 The...

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Unformatted text preview: 154 9. CHAPTER 6 The ranks of the combined samples are Value Rank Sample 51 1 Y 59 2 Y 64 4 X 64 4 Y 64 4 Y 66 6 X 69 7 X 72 8 X 74 95 X 74 95 Y 75 11 5 X 75 11 5 Y 77 14 X 77 14 X 77 14 Y Y 80 16 5 80 16 5 Y 81 18 5 Y 81 18 5 Y 83 20 5 X 83 20 5 Y 85 22 5 X 85 22 5 Y 86 24 Y 88 25 X 91 26 X ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ 0 versus H1 : µX µY ¡ ¡ µY 0. ¡ ¡ The null and alternate hypotheses are H0 : µX The test statistic W is the sum of the ranks corresponding to the X sample. ¡ 168. The sample sizes are m 12 and n ¡ ¡ W 14. Since n and m are both greater than 8, compute the z-score of W and use the z table. 1 12 £ ¥ ¢ ¢ ¤ ¢ n 12 £ ¥ ¢ ¡ ¡ mn m n 0 31. ¡ mm ¨ W z ¤ Since the alternate hypothesis is of the form µX µY ∆, the P-value is the sum of the areas to the right of z 0 31 and to the left of z 0 31. From the z table, P 0 3783 0 3783 0 7566. ¡ ¨ ¡ ¨ ¢ ¨ ¡ ¡ ¨ ¡ ¡ ¨ ¡ We cannot conclude that the mean scores differ. Section 6.10 1. (a) Let p1 represent the probability that a randomly chosen rivet meets the specification, let p 2 represent the probability that it is too short, and let p3 represent the probability that it is too long. Then the null hypothesis is H0 : p1 0 90 p2 0 05 p3 0 05 ¨ ¡  ¨ ¡  ¨ ¡ ...
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This note was uploaded on 12/20/2011 for the course STA 3163 taught by Professor Mattgilg during the Fall '11 term at UNF.

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