Statistics Homework Solutions 165

Statistics Homework Solutions 165 - 165 SUPPLEMENTARY...

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Unformatted text preview: 165 SUPPLEMENTARY EXERCISES FOR CHAPTER 6 2 9723 ¨ ¨ 0 1056, and P X 0 0038. ¡¥ ¤ ¨ ¡¥ 3 0277 ¨ Therefore P X § ¨ ¤ The probability that the equipment will be recalibrated is equal to 0.1056 + 0.0038 = 0.1094. ¡ 1 87. ¡ £ ¥ ¨ ¡ ¤ ¨ £¥ ¨ ¡ ¨ ¡ ¡ ¨ ¡ ¤ Value Rank Sample 10 1 Y 9 2 Y 8 3 Y 7 4 Y 6 5 Y 5 6 Y 4 7 Y 1 8 X 2 9 X 3 10 X 4 11 X 5 12 X 6 13 X 7 14 X 20 15 5 X 20 15 5 Y 21 17 Y 22 18 Y 23 19 Y 24 20 Y 25 21 Y 26 22 Y 27 23 Y 40 24 X 50 25 X 60 26 X 70 27 X 80 28 X 90 29 X 100 30 X ¡ ¡ ¡ ¡ ¡ ¡ ¨ ¨ ¡ (b) The ranks of the combined samples are ¨ 17. (a) Both samples have a median of 20. ¡¥ ¤ We cannot conclude that the failure rate on line 3 is less than 0.10. 0 1228. ¨ ¡ Since there are four samples altogether, the Bonferroni-adjusted P-value is 4 0 0307 ¡ p0 , the P-value is the area to the left of z ¡ ¢ Since the alternate hypothesis is of the form p P 0 0307. 1 87, so ¨ 0 10 495 ¡ 0 10 1 ¡ 0 10 0 10. ¨ ¡ 0 074747 0 10 versus H1 : p § z 0 074747. ¨ 37 495 ¡ 495, p The null and alternate hypotheses are H0 : p ¨ 458 ¡ 37 £ 37, n ¡ X ¨ 15. ...
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This note was uploaded on 12/20/2011 for the course STA 3163 taught by Professor Mattgilg during the Fall '11 term at UNF.

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