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Statistics Homework Solutions 185

Statistics Homework Solutions 185 - 185 SUPPLEMENTARY...

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SUPPLEMENTARY EXERCISES FOR CHAPTER 7 185 There are 14 2 12 degrees of freedom. t 12 025 2 179. Therefore a 95% confidence interval for the slope is 0 00736635 2 179 0 00346467 ,or 0 00018 0 01492 . (c) x 20, y β 0 β 1 20 0 188823. s y s 1 n x x 2 n i 1 x i x 2 0 0199997. There are 12 degrees of freedom. t 12 025 2 179. Therefore a 95% confidence interval for the mean response is 0 188823 2 179 0 0199997 , or (0.145, 0.232). (d) x 20, y β 0 β 1 20 0 188823. s pred s 1 1 n x x 2 n i 1 x i x 2 0 073622. There are 12 degrees of freedom. t 12 05 1 782. Therefore a 90% prediction interval is 0 188823 1 782 0 073622 , or (0.0576, 0.320). 9. (a) ln y β 0 β 1 ln x , where β 0 ln k and β 1 r . (b) Let u i ln x i and let v i ln y i . u 1 755803, v 0 563989, n i 1 u i u 2 0 376685, n i 1 v i v 2 0 160487, n i 1 u i u v i v 0 244969, n 5. β 1 n i 1 u i u v i v n i 1 u i u 2 0 650328 and β 0 v β 1 u 1 705838. The least-squares line is ln
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