Statistics Homework Solutions 188

# Statistics Homework Solutions 188 - 188 CHAPTER 7 1 225 86...

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188 CHAPTER 7 (f) x 225, y β 0 β 1 225 86 483333. s y s 1 n x x 2 n i 1 x i x 2 0 179490. There are 10 degrees of freedom. t 10 025 2 228. Therefore a 95% confidence interval for the mean response is 86 483333 2 228 0 179490 , or (86.083, 86.883). (g) x 225, y β 0 β 1 225 86 483333. s pred s 1 1 n x x 2 n i 1 x i x 2 0 647160. There are 10 degrees of freedom. t 10 025 2 228. Therefore a 95% prediction interval is 86 483333 2 228 0 647160 , or (85.041, 87.925). 15. (ii). The standard deviation s y is not given in the output. To compute s y , the quantity n i 1 x i x 2 must be known. 17. (a) If f 1 2 then 1 f 2. The estimate is t 145 736 0 05180 2 145 63. (b) Yes. r R-Sq 0 988. Note that r is negative because the slope of the least-squares line is negative. (c) If f 1 then 1 f 1. The estimate is
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