Statistics Homework Solutions 202

Statistics Homework Solutions 202 - 202 CHAPTER 8 Cubic...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 202 CHAPTER 8 Cubic Model 15 Residual 10 5 There is no obvious pattern to the residual plot, so the cubic model appears to fit well. 0 −5 −10 400 ¨ ¡¥ ¨ ¡¥ ¡¥ ¤ 237 02. ¨ 176 80. ¨ ¡¥ ¢¥ ¡¥ ¢¥ 0 164 75 ¨ ¡¥ ¤ ¨ ¨ ¤ ¥ ¥ ¤ ¨ ¤ ¥ ¨ ¨ ¢ ¨ ¤ ¥ ¡ ¨ ¢ ¨ ¤ ¨ ¡ ¨ ¢ ¥ ¡ ¨ ¢ ¤ ¡ ¨ ¨ ¤ ¡ ¡ ¨ ¢ ¥ ¡ ¨ ¢ ¡ ¡ ¨ ¤ ¡ ¨ ¨ ¤ ¤ ¡ ¤ ¢ ¥ ¡ ¨ ¤ 163 89. 180 78. ¨ ¨ ¤ 0 164 100 ¨ ¤ 0 2106 200 236 39. ¨ ¢¥ 0 3660 1400 187 56. 234 18. 0 16047 200 0 5198 75 ¤ 0 5198 100 ¡¥ ¨ 0 41641 1400 0 16047 300 0 2106 300 0 37820 1400 0 164 150 ¨ ¢ ¨ ¡ 380 1 ¨ 301 8 ¤ 320 59 Under model 2, the prediction is ¥ 0 3660 1600 301 8 (c) Under model 1, the prediction is ¡ ¡ Under model 3, the prediction is ¨ 0 37820 1600 0 41641 1600 ¤ ¨ 380 1 Under model 2, the prediction is 0 2106 400 166 55. ¡¥ ¢ 320 59 0 5198 150 182 52. ¨ ¨ 0 3660 1500 301 8 (b) Under model 1, the prediction is ¤ Under model 3, the prediction is ¨ ¡ ¡ Under model 3, the prediction is 0 41641 1500 ¥ 380 1 0 16047 400 ¡ Under model 2, the prediction is 0 37820 1500 ¨ 320 59 9. (a) Under model 1, the prediction is ¤ 200 300 Fitted Value ¡¥ 100 ¨ −15 0 (d) (iv). The output does not provide much to choose from between the two-variable models. In the three-variable model, none of the coefficients are significantly different from 0, even though they were significant in the two-variable models. This suggest collinearity. S = 12.308 Coef 40.751 0.54013 R-sq = 4.2% Analysis of Variance StDev 5.4533 0.61141 T 7.4728 0.88341 R-sq(adj) = ¡ Linear Model Predictor Constant Hardwood 1 2% ¨ 11. (a) P 0.000 0.389 ...
View Full Document

Ask a homework question - tutors are online