Statistics Homework Solutions 233

Statistics Homework Solutions 233 - n 5. R 131. From the...

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SECTION 10.4 233 3. Yes, the only information needed to compute the control limits is p and the sample size n . In this case, n 100, and p 622 50 100 0 1244. The control limits are p 3 p 1 p n , so LCL = 0.0254 and UCL = 0.2234. 5. (iv). The sample size must be large enough so the mean number of defectives per sample is at least 10. 7. It was out of control. The UCL is 45.82. Section 10.4 1. (a) No samples need be deleted. (b) The estimate of σ X is A 2 R 3. The sample size is
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Unformatted text preview: n 5. R 131. From the control chart table, A 2 577. Therefore X 577 131 3 0252. (c) 5 10 15 20-0.4-0.3-0.2-0.1 0.1 0.2 0.3 0.4 Sample Number Cumulative Sum CUSUM Chart UCL = 0.101 LCL = -0.101 (d) The process is out of control on sample 8. (e) The Western Electric rules specify that the process is out of control on sample 8. 3. (a) No samples need be deleted....
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